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The cost of a car rental is $25 per day plus 22 per mile. You are on a daily budget of $90. Write and solve an inequality to f

lara31 [8.8K]

Answer: You can drive, at most, 2.95 miles per day.

x ≤ 2.95

Step-by-step explanation:

In a single day, you can spend at most $90

Then if C represents the cost of renting the car, then we will have the inequality:

C ≤ $90

Now let's find the equation for C.

We know that we have a fixed cost of $25 plus $22 per mile, then if you drive x miles, the total cost will be $25 plus x times $22, or:

C = $25 + x*$22.

We can now replace that in the inequality:

$25 + x*$22 ≤ $90

Now let's isolate the variable x

x*$22 ≤ $90 - $25

x*$22 ≤ $65

x ≤ $65/$22 = 2.95

x ≤ 2.95

You can drive at most, 2.95 miles per day.

To find other inequalities with the same solution we can start with the solution:

x ≤ 2.95

Now let's multiply both sides by a number (the units of the number can be dollars, in that way we can make a similar problem)

Let's multiply both sides by $10:

x*$10 ≤ 2.95*$10 = $29.5

x*$10 ≤ $29.5

Now let's add the same number in both sides, for example, $5.

x*$10 + $5 ≤ $29.5 + $5 = $34.5

x*$10 + $5 ≤ $34.5

We could write this problem as:

"To rent a cab in your city, you have an initial cost of $5, plus $10 for each mile driven. How many miles could you drive if at most you can spend $34.50?"

You could be more creative with the problem, but this is the way in which you can craft problems of this type when you already know the solution.

5 0

2 years ago

Write a polynomial function in standard form with zeros at −3, −1, and 1.

Annette [7]

Answer:

$f(x) = {x}^{3} + 3 {x}^{2} - x -3$

Step-by-step explanation:

The given polynomial has zeros at:

x=−3, x=−1, and x=1.

This means that:

x+3, x+1, and x-1 are all factors of this polynomial.

The factored form of this polynomial is :

$f(x) = (x + 3)(x + 1)(x - 1)$

We expand the last two factors using difference of two squares.

$f(x) = (x + 3)( {x}^{2} - 1)$

$f(x) = x ( {x}^{2} - 1) + 3( {x}^{2} - 1)$

$f(x) = {x}^{3} - x+ 3 {x}^{2} -3$

$f(x) = {x}^{3} + 3 {x}^{2} - x -3$

This is the standard form because it is now in decreasing powers of x.

8 0

3 years ago

Help, adding extra text so that I can post this question

GREYUIT [131]

The answer 0.1, 0.136, 0.652, 0.87

8 0

2 years ago

Read 2 more answers

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago

PLEASE ANSWERRR!!!!!

lawyer [7]

Answer:

I don't know how to do this. I'm so sorry that I couldn't help!!

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers