13. Growing exponentially to carrying capacity
14. Population is dying down down after reaching carrying capacity
Answer:
l=k/4+7/4
Step-by-step explanation:
Answer:
In the next 31 years
Step-by-step explanation:
In this question, we are tasked with calculating the number of years it will take for a school’s population to reach a certain amount of it is increasing at a certain rate.
We can use a mathematical exponential approach to solve this.
Let’s say;
P = I( 1 + r)^t
where P is the projected population at 926
I is the initial population at 502
r is the percentage change or rate at 2% which is same as 2/100 = 0.02
and t is time
Plugging these values, we have
926 = 502(1 + 0.02)^t
Divide through by 502
1.845 = 1.02^t
take the logarithm of both sides
log 1.845 = tlog 1.02
t = log 1.845/log 1.02
t = 30.9 = 31 years
Answer:
$475
Step-by-step explanation:
7+6+7+5 = 25
25*19 = 475
