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ryzh [129]
4 years ago
13

Which of the following shows the division problem below in synthetic division form?

Mathematics
1 answer:
lara [203]4 years ago
6 0

Answer: D

Step-by-step explanation:

In synthetic division, if the divisor is an expression like x+3, you should always switch it to if x+3 were equal to 0.

x+3=0\\x=-3

So, you should use -3. The only options with -3 are B and D.

The coefficients for the dividend are 7, -2, and 4, so D is the correct answer.

Hope this helps! If you still have questions, please ask.

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Give triangle abc is congruent to triangle def find x
Karolina [17]

Answer:

x=9

Step-by-step explanation:

FE is 3x-7

since ΔABC≅ΔDEF the equivalent of FE is CB, or BC...which is 20

3x-7=20

3x=27

x=9

6 0
3 years ago
Suppose u = (1,2,3), v = (2, -3, -4), and w = (1,0,-2). (a) Find u-2v + 3w. (b) Write the vector (3,4,5) as a linear combination
marishachu [46]
<h2>Answer with explanation:</h2>

We are given vectors u,v and w as follows:

      u=(1,2,3)\,\ v=(2,-3,-4),\ and\ w=(1,0,-2)

(a)

Now we are asked to find the value of:

  u-2v+3w

The value is calculated as follows:

u-2v+3w=(1,2,3)-2(2,-3,-4)+3(1,0,-2)\\\\i.e.\\\\u-2v+3w=(1,2,3)+(-2\times 2,-2\times -3,-2\times -4)+(3\times 1,3\times 0,3\times -2)\\\\i.e.\\\\u-2v+3w=(1,2,3)+(-4,6,8)+(3,0,-6)\\\\i.e.\\\\u-2v+3w=(1-4+3,2+6+0,3+8-6)\\\\i.e.\\\\u-2v+3w=(0,8,5)

                              Hence,

                 u-2v+3w=(0,8,5)

(b)

We are asked to represent (3,4,5) as a linear combination of u, v, and w.

Let:

(3,4,5)=au+bv+cw

(3,4,5)=a(1,2,3)+b(2,-3,-4)+c(1,0,-2)

i.e.

(3,4,5)=(a,2a,3a)+(2b,-3b,-4b)+(c,0,-2c)\\\\i.e.\\\\(3,4,5)=(a+2b+c,2a-3b,3a-4b-2c)\\\\i.e.\\\\a+2b+c=3----------(1)

2a-3b=4-------------(2)

3a-4b-2c=5------------(3)

on multiplying equation(1) by 2 an then adding equation (1) to equation (3)

5a=11\\\\i.e.\\\\a=\dfrac{11}{5}

on putting the value of a in equation (2) we get:

2\times \dfrac{11}{5}-3b=4\\\\i.e.\\\\\dfrac{22}{5}-3b=4\\\\i.e.\\\\3b=\dfrac{22}{5}-4\\\\i.e.\\\\3b=\dfrac{2}{5}\\\\i.e.\\\\b=\dfrac{2}{15}

Now on putting the value of a and b in equation (1)

\dfrac{11}{5}+2\times \dfrac{2}{15}+c=3\\\\i.e.\\\\\dfrac{11}{5}+\dfrac{4}{15}+c=3\\\\i.e.\\\\c=3-\dfrac{11}{5}-\dfrac{4}{15}\\\\i.e.\\\\c=\dfrac{3\times 15-11\times 3-4}{15}\\\\i.e.\\\\c=\dfrac{45-33-4}{15}\\\\i.e.\\\\c=\dfrac{8}{15}

Hence, we have:

(3,4,5)=\dfrac{11}{5}(1,2,3)+\dfrac{2}{15}(2,-3,-4)+\dfrac{8}{15}(1,0,-2)\\\\i.e.\\\\(3,4,5)=\dfrac{11}{5}u+\dfrac{2}{15}v+\dfrac{8}{15}w

5 0
4 years ago
What is the distance between -12 and 5?​
Vilka [71]

Answer:

7

Step-by-step explanation:

<em>PLZ TELL ME IF IM WRONG</em>

3 0
3 years ago
Can anybody please help how to do these!! NO LINKS<br><br>​
Masja [62]

Answer:

22.

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23.

(rcos \theta) ^{2}  + (rsin \theta) ^{2}  = 25

Step-by-step explanation:

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and y with rsin\theta

3 0
3 years ago
Find the value of x 110, 40, 80
Deffense [45]
The correct answer would be 130
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