This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>
It is 10 yard line. Becuase it ends on zero.
Answer:
i dont think you can do that sorry :( it would come out with a decimal/leftover
Step-by-step explanation:
