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Y_Kistochka [10]

2 years ago

8

A triangular pyramid has a surface area of 174 square feet. It is made up of equilateral triangles with side lengths of 10 feet.

What is the slant height?

1 answer:

emmainna [20.7K]2 years ago

6 0

Answer:

Slant height = 7.07 ft to nearest hundredth.

Step-by-step explanation:

The slant height = height of one of the triangular sides

Using Pythagoras:

S^2 = 1/2 * 10^2 + 10^2 = 50 ft.

S = √50 = 7.071

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The area of the park without fountain is about 819.76 square yards.

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3 years ago

In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank

fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) $Amount \ of \, water \ remaining \ in \, the \ tank \ is \ \frac{x^3(6-\pi) }{6}$

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The volume of the sphere = $\frac{4}{3} \pi r^3$

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = $\frac{4}{3} \pi \frac{x^3}{8}$ = $\frac{1}{6} \pi x^3$

For tank B

Volume of tank = x³

The volume of the spheres = $8 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = $8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}$

For tank C

Volume of tank = x³

The volume of the spheres = $64 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = $64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}$

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The volume of the spheres = $512 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = $512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}$

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = $x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}$

$Amount \ of \ water \, remaining \, in \, the \ tank = \frac{x^3(6-\pi) }{6}$ .

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3 years ago

LeBron James is a very popular professional basketball player in the US. Each game, players can commit a maximum of 666 personal

andrezito [222]

Answer:

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Step-by-step explanation:

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3 years ago

Describe a time when you use math outside of school ( pls I need help with this writing prompt)

Serga [27]

Answer:

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Step-by-step explanation:

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3 years ago

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Marion bought 14 packages of plastic frog and lizard fishing lures. She bought frog lures in packages of 4 and lizard lures in p

tatuchka [14]

Answer:

Marion bought 6 frog lures and 8 lizard fishing lures.

Step-by-step explanation:

Let $f$ represent frog lures and $l$ represent lizard lures.

The total packages Marion bought is

$f+l=14...eqn1$

If she bought frog lures in packages of 4 and lizard lures in packages of 6 for a total of 72 lures, then

$4f+6l=72...eqn2$

We make $f$ the subject in equation 1 and put it into equation 2 to get;

$f=14-l...eqn3$

We put equation 3 into equation 2 to get;

$4(14-l)+6l=72$

$\Righttarrow 2(14-l)+3l=36$

We expand the bracket to get;

$28-2l+3l=36$

$-2l+3l=36-28$

$l=8$

We put $l=8$ into equation 3 to get;

$f=14-8$

$f=6$

Therefore Marion bought 6 frog lures and 8 lizard fishing lures.

6 0

3 years ago