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Y_Kistochka [10]
2 years ago
8

A triangular pyramid has a surface area of 174 square feet. It is made up of equilateral triangles with side lengths of 10 feet.

What is the slant height?
Mathematics
1 answer:
emmainna [20.7K]2 years ago
6 0

Answer:

Slant height = 7.07 ft to nearest hundredth.

Step-by-step explanation:

The slant height = height of one of the triangular sides

Using Pythagoras:

S^2 =  1/2 * 10^2 + 10^2 = 50 ft.

S = √50 = 7.071

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Is 5 5/6 + 1 3/4=5 1/12 reasonable
ira [324]

Answer:

No, it is unreasonable.

Step-by-step explanation:

5/5/6+1/3/4=35/6+7/4

=70/12+21/12

=91/12

=7 7/12

4 0
2 years ago
The symphonic choir and the jazz choir are recording songs for an album. The album can be no more than 72 minutes long. The jazz
zimovet [89]

Answer:

The symphonic choir can record a maximum of 14 songs.

Step-by-step explanation:

We know that the album cannot be more than 72 minutes long, and the jazz choir records a total of 7 (3min) = 21  song minutes.

If we call c the number of songs the symphonic choir records , and each song is 3.5 minute long, then the song minutes for the symphonic choir are 3.5c; therefore, we have the inequality

3.5c+21\leq 72<em> (this says the song minutes for jazz choir plus song minutes for symphonic choice cannot exceed 72 minutes )</em>

We solve this inequality by subtracting 21 from both sides and then dividing by 3.5:

3.5c\leq 51

$c\leq \frac{51}{3.5} $

c\leq 14.47

The maximum integer value c can take is 14; therefore, the maximum number of songs the symphonic choir can record is 14 songs.

3 0
3 years ago
A box in the shape of a rectangular prism has a dimension of 30 meters x 27 meters x 28 meters what is the surface area of the b
erastovalidia [21]
Your answer would be <span> 4812 m².</span>
5 0
2 years ago
Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
Given that (5,-8) is on the graph of f(x), find
My name is Ann [436]

Answer:

The corresponding point for the function  f(x + 2) is (3 , -8)

Step-by-step explanation:

* Lets talk about the transformation

- If the function f(x) translated horizontally to the right  by h units,

 then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left  by h units,

 then the new function g(x) = f(x + h)

* Lets solve the problem

- There is a graph of f(x)

- Point (5 , -8) lies on the graph of f(x)

- The graph of f(x) change to f(x + 2)

∵ f(x) ⇒ f(x + 2)

∵ If the function f(x) translated horizontally to the left  by h units,

  then the new function g(x) = f(x + h)

∴ f(x) translated horizontally 2 units to the left

∴ Any point on the graph its x-coordinate translated 2 units

  to the left

∴ The x-coordinate of any point on the graph is subtracted by 2

∵ Point (5 , -8) lies on the graph

∴ Its corresponding point is (5 - 2 , -8) = (3 , -8)

* The corresponding point for the function  f(x + 2) is (3 , -8)

7 0
3 years ago
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