Question

A circular pool with a 10 foot diameter is surrounded by a deck. What is the area of the deck which surrounds the pool? use 3.14

Answer 1

Answer:

146.5 sq. feet.

Step-by-step explanation:

Area of the deck = Large Square (with 15 ft side) - Circular Pool (with radius 10/2=5)

Large Square area = $s^2=(15)^2=225$

Circular Pool area = $\pi r^2=\pi (5)^2=\pi (25)\\=25(3.14)\\=78.5$

Thus, area of deck surrounding pool = $225-78.5=146.5$ sq. feet

Answer 2

ANSWER

$146.5 {ft}^{2}$

EXPLANATION

The circular pool has diameter,

$d = 10ft$

This means the radius is;

$r = \frac{10}{2} = 5ft$

The area of the pool is

$= \pi \: {r}^{2}$

$=(3.14) \times {5}^{2}$

$= 78.5$

The area of the deck is equal to the area of the square minus area of circular pool.

${15}^{2} - 78.5 = 146.5 {ft}^{2}$