Question

80 POINTS! NO LINKS

Answer 1

The amount of ribbon needed to go around a package that had a length 2x² + 3x -5/(x² + x - 3) centimeters and width x² - x - 5 / (x² + x - 3) is

$\frac{(2x^2+3x-5)(x^2-x-5)}{(x^2+x-3)^2}$

What is an equation?

An equation is an expression that shows the relationship between two or more number and variables.

The  length 2x² + 3x -5/(x² + x - 3) centimeters and width x² - x - 5 / (x² + x - 3) centimeters. Hence:

$Area=\frac{2x^2+3x-5}{x^2+x-3} *\frac{x^2-x-5}{x^2+x-3} =\frac{(2x^2+3x-5)(x^2-x-5)}{(x^2+x-3)^2}$

The amount of ribbon needed to go around a package that had a length 2x² + 3x -5/(x² + x - 3) centimeters and width x² - x - 5 / (x² + x - 3) is

$\frac{(2x^2+3x-5)(x^2-x-5)}{(x^2+x-3)^2}$

Find out more on equation at: brainly.com/question/2972832

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