Answer:
$1125000
Step-by-step explanation:
45,000 x 25 = 1125000
Since the question didn't specify what values to calculate, I will assume that it is how much money was issued in total.
Step-by-step explanation:
let the first-day ride be x
Then the second-day ride will be
=1.5
x
The third-day ride will be=1.5(1.5x)
The Fourth-day ride will be=1.5*1.5(1.5x)
hence for the four days the distance covered is
65=x+1.5x+1.5*1.5x+1.5*1.5*1.5x
65=x+1.5x+2.25x+3.375x
65=8.125x
divide both sides by 8.125 we have
x=65/8.125
x=8mile
the first-day ride be x=8miles
the second-day ride will be
=1.5
x
=1.5*8= 12miles
The third-day ride will be=1.5(1.5x) = 18miles
The Fourth-day ride will be=1.5*1.5(1.5x) = 27miles
Answer:
1. 80
2. 2400
Step-by-step explanation:
1. what is the change in Dan's total pay for each copy of math is fun he sells?
2. what is Dan's total pay if he doesn't sell any copies of math is fun?
Given
y=80x + 2400
When x=0
y=80(0)+2400
=0+2400
=2400
When x=1
y=80x + 2400
=80(1) + 2400
=80+2400
=2480
change in Dan's total pay for each copy of math is fun he sells is
= 2480 - 2400
=80
2. Dan's total pay if he doesn't sell any copies of math is fun?
y=80x+2400
When x=0
y=80(0)+2400
=0+2400
=2400
a = amount deposited at 3.5%
b = amount deposited at 4.5%
we know that "b" is twice as much as "a", thus b = 2a.
![\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{3.5\% of a}}{\left( \cfrac{3.5}{100} \right)a}\implies 0.035a \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{4.5\% of 2a}}{\left( \cfrac{4.5}{100} \right)2a}\implies 0.045(2a)](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Ba%5C%25%20of%20b%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20%5Cleft%28%20%5Ccfrac%7Ba%7D%7B100%7D%20%5Cright%29%5Ccdot%20b%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D~%5Chspace%7B5em%7D%5Cstackrel%7B%5Ctextit%7B3.5%5C%25%20of%20a%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B3.5%7D%7B100%7D%20%5Cright%29a%7D%5Cimplies%200.035a%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Ba%5C%25%20of%20b%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20%5Cleft%28%20%5Ccfrac%7Ba%7D%7B100%7D%20%5Cright%29%5Ccdot%20b%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D~%5Chspace%7B5em%7D%5Cstackrel%7B%5Ctextit%7B4.5%5C%25%20of%202a%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B4.5%7D%7B100%7D%20%5Cright%292a%7D%5Cimplies%200.045%282a%29)
we also know that whatever "a" amount is, their sum is 2250, thus
