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Sindrei [870]
2 years ago
9

A bag of dozen oranges was selling for $3. The manager of the store decided to add some oranges to the bag, but not to change th

e $3 sticker price on the bag. Now the price of the oranges was actually $2 a dozen. How many oranges were added to the bag
Mathematics
1 answer:
Kitty [74]2 years ago
8 0

Answer:

A fruit seller buys some oranges and by selling 40% of them he realizes the cost price of all the oranges. As the oranges being to grow over-ripe, he reduces the price and sells 80% of the remaining oranges at half the previous rate of profit.

Step-by-step explanation:

You might be interested in
What is the distance between point P and point R?
stealth61 [152]

Answer:

PR = 10

Step-by-step explanation:

PR = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The coordinates for P and R are (0,4) and (-6,-4) respectively.

So you plug in the values:

PR = \sqrt{(-6-0)^2+(-4-4)^2}

PR = \sqrt{(-6)^2+(-8)^2}

PR = \sqrt{36+64}

PR = \sqrt{100}

PR = 10

3 0
3 years ago
The minimum age for entry is 10 years old. Let x represent the age allowed for entry.
natita [175]

Answer:

x\geq 10

6 0
3 years ago
Jon is looking into a 4250 vacation package that is offered for 25% off. there's a 9% resort fee added on to the total. How much
bazaltina [42]
When you want to find a percent of a number you do this:
given number/ 1   multiplied by   percentage/100

so in this question its a multiple step 

start with finding 25 percent of 4250 which is= 1062.5
so thats how much the discount is so the amount after the 25% discount is:
4250-1062.5= 3187.5

then you have to add 9% due to fees
so you find 9% of 3187.5 which is= 286.875
so you add 286.875 to 3187.5 gives you= 3437.375 in total cost for the vacation package
8 0
3 years ago
In 2015, there were roughly 1x10^6 high school football players and 2x10^3 professional football players in the United States.
melisa1 [442]

Answer:

500.

Step-by-step explanation:

(1 * 10^6) / (2 * 10^3)

= 1/2 * 10^6/10^3

= 0.5 * 10^3

= 5 * 10^2

= 500.

5 0
3 years ago
5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0
3 years ago
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