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Vlad [161]
3 years ago
11

Find an equation for the nth term of the arithmetic sequence. -15, -6, 3, 12, ...

Mathematics
1 answer:
Mariulka [41]3 years ago
5 0

Answer: t_{n}=-15+9(n-1)

Step-by-step explanation:

The formula for finding the nth term of an arithmetic sequence is given as:

t_{n}=a+(n-1)d

a = first term = -15

d = common difference = -6 - (-15) = 9

n = number of terms

substituting into the formula , we have :

t_{n} = -15+(n-1)9

t_{n}=-15+9(n-1)

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In 1980, the number of high school dropouts in a country was 5217 thousand. By 2008, this number had decreased to 3120 thousand.
Veseljchak [2.6K]

Answer:

74893 students per year

Step-by-step explanation:

The Average rate of change is calculated as

= Difference in number of students / Difference in years

= 3120 thousand - 5217 thousands/ 2008 - 1980

= (3120000 - 5217000)/(2008 - 1980)

= -2097000/28

= -74892.857143 per year

Therefore, the average rate of change

per year in the number of high school dropouts is approximately 74893 students per year

8 0
3 years ago
What is the coefficient of the variable in the expression 6-4x-8x+2
Daniel [21]

I think the trick is to add the two middle terms together.  (And the 2 end terms).

8 - 12x

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8 is a constant.

The coefficient always goes with a variable.

3x^2 + 2x + 5

Nothing can be combined.  The leading coefficient is 3 (which goes with the greatest power of the variable x^2 in this case) and the other coefficient is 2. 5 is a constant.  

6 0
3 years ago
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mestny [16]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
I only need questions 2 and 3 it’s urgent could someone please help?
marta [7]

Answer:

a = x-intercept(s):  ( 3 , 0 )

y-intercept(s):  

( 0 , 6 )

B = x-intercept(s):  

( 10 , 0 )

y-intercept(s):  

( 0 , 4 )

Step-by-step explanation:

#

3 0
2 years ago
I need step by step please 3(x-2)^2+1=13
Romashka-Z-Leto [24]

Answer:

x_{1} = 0. \:  \:  \:  x_{2} = 4

Step-by-step explanation:

3(x - 2)^{2}  + 1 = 3

3( {x}^{2}  - 4x + 4) + 1 = 13

{3x}^{2}  - 12x + 12 + 1 = 13

{3x}^{2}  - 12x + 13 = 13

{3x}^{2}  - 12x = 0

x \times (x - 4) = 0

x = 0

x - 4 = 0

\boxed{\green{x_{1} = 0. \:  \:  \:  x_{2} = 4}}

7 0
2 years ago
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