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Lyrx [107]
2 years ago
13

A square has a side that measures 5. 5 units. What is the area of a circle with a circumference that equals the perimeter of the

square? Use 3. 14 for π, and round your answer to the nearest hundredth. 38. 47 units2 94. 99 units2 153. 86 units2 379. 94 units2.
Mathematics
1 answer:
Eva8 [605]2 years ago
7 0

The area of the circle whose circumference is equal to the perimeter of the square is 38.47 squared units.

<h3>What is circumference and area of the circle?</h3>

Circumference of the circle is the length of its boundary. It can given as,

P=2\pi r

The area of the circle is the space occupied by it. It can be given as,

A=\pi r^2

Here (<em>r</em>) is the radius of the circle.

A square has a side that measures 5. 5 units. The perimeter of the square is the equal to the 4 times of its side. Thus its perimeter is,

P=4\times5.5\\P=22\rm\; units

The circumference of the circle is equal to the perimeter of the square. Thus the radius (<em>r</em>) of circle is,

P=2\pi r\\22=2\times\pi r\\r\approx3.5\rm\; units

The area of this circle is,

A=\pi r^2\\A=3.14\times (3.5)^2\\A=38.465\\A\approx 38.47\rm\; units^2

Hence the area of the circle whose circumference is equal to the perimeter of the square is 38.47 squared units.

Learn more about the circumference and area of the circle here;

brainly.com/question/402655

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According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women
blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : P(X=r) =^nC_r p^r q^{n-r}

At x = 2

P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}

P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}

P(X=2) =8.8009 \times 10^{-7}

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So,  P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}

 P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})

P(X=r) =9.9439 \times 10^{-6}

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=0.2360

8 0
3 years ago
What would be the answer for this one?
PilotLPTM [1.2K]

Hi,

Using Thalès, x/14=9/12

==>x=9*14/12

==>x=21/2

==>x=10.5

Answer D

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Count the total number of objects. That is the denominator, which goes under the line. Then, only count the stars. That number is the numerator, which goes on top.
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Answer:

a or b

Step-by-step explanation:

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