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Lyrx [107]
2 years ago
13

A square has a side that measures 5. 5 units. What is the area of a circle with a circumference that equals the perimeter of the

square? Use 3. 14 for π, and round your answer to the nearest hundredth. 38. 47 units2 94. 99 units2 153. 86 units2 379. 94 units2.
Mathematics
1 answer:
Eva8 [605]2 years ago
7 0

The area of the circle whose circumference is equal to the perimeter of the square is 38.47 squared units.

<h3>What is circumference and area of the circle?</h3>

Circumference of the circle is the length of its boundary. It can given as,

P=2\pi r

The area of the circle is the space occupied by it. It can be given as,

A=\pi r^2

Here (<em>r</em>) is the radius of the circle.

A square has a side that measures 5. 5 units. The perimeter of the square is the equal to the 4 times of its side. Thus its perimeter is,

P=4\times5.5\\P=22\rm\; units

The circumference of the circle is equal to the perimeter of the square. Thus the radius (<em>r</em>) of circle is,

P=2\pi r\\22=2\times\pi r\\r\approx3.5\rm\; units

The area of this circle is,

A=\pi r^2\\A=3.14\times (3.5)^2\\A=38.465\\A\approx 38.47\rm\; units^2

Hence the area of the circle whose circumference is equal to the perimeter of the square is 38.47 squared units.

Learn more about the circumference and area of the circle here;

brainly.com/question/402655

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s2008m [1.1K]

Answers:

  • Problem 1)  40 degrees
  • Problem 2) 84 degrees
  • Problem 3) 110 degrees

===============================================

Explanation:

For these questions, we'll use the inscribed angle theorem. This says that the inscribed angle is half the measure of the arc it cuts off. An inscribed angle is one where the vertex of the angle lies on the circle, as problem 1 indicates.

For problem 1, the arc measure is 80 degrees, so half that is 40. This is the measure of the unknown inscribed angle.

Problem 2 will have us work in reverse to double the inscribed angle 42 to get 84.

-------------------

For problem 3, we need to determine angle DEP. But first, we'll need Thales Theorem which is a special case of the inscribed angle theorem. This theorem states that if you have a semicircle, then any inscribed angle will always be 90 degrees. This is a handy way to form 90 degree angles if all you have is a compass and straightedge.

This all means that angle DEF is a right angle and 90 degrees.

So,

(angle DEP) + (angle PEF) = angle DEF

(angle DEP) + (35) = 90

angle DEP = 90 - 35

angle DEP = 55

The inscribed angle DEP cuts off the arc we want to find. Using the inscribed angle theorem, we double 55 to get 110 which is the measure of minor arc FD.

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3 years ago
Given:<br> f(x)=x^2<br> g(x)=x-1<br> Find f(g(2))+g(f(-1))
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Answer:

-1

Step-by-step explanation:

First, we need to work out the left-hand side.

  • find g(2) → g(2) = 2 - 1 which is 1
  • next, find f(1) → f(1) = 1³ which is 1

Now, we can work out the right hand side.

  • find f(-1) → f(-1) = -1³ which is -1
  • then, find g(-1) → g(-1) = -1 - 1 = -2

Finally we can work out the full sum: 1 + -2 = -1.

Hope this helps!

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