The measure of the segment DF is 2 2/3
<h3>Segment Addition postulate</h3>
The segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.
A line is a distance between two points. From the given line;
DF = F - D
Given the following
F = -1 1/3
D = -4
Substitute
DF = -1 1/3 - (-4)
DF = 4 - 4/3
DF = 8/3
DF =2 2/3
Hence the measure of the segment DF is 2 2/3
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Answer:
2.72 × 10^8 seconds
Step-by-step explanation:
1. Organize the given information to help you create the equation:
- Light travels 1.86 × 10^5 miles per 1 second
- Light travels 5.062 × 10^13 miles per <em>n</em> seconds
- Need to solve for <em>n</em>
2. Set up the equation (Make sure that both numerators and both denominators match units, so the seconds are either both on top or both on bottom, NOT switched):
= 
3. Cross multiply (Multiply the first fraction's numerator by the second's denominator, and vice versa. It doesn't matter what number is on which side of the = sign)
<em>n </em>× (1.86 × 10^5) = 5.062 × 10^13
4. Solve for <em>n</em> by isolating the variable and dividing.
= 
<em>n</em> = 
<em>n </em>= 2.72 × 10^8 (Make sure to include the unit, seconds)

The required values are :
Length = 33 m
Breadth (width) = 30 m
solution is in attachment ~