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2 years ago

Hi, I'm struggling on level 2 for

Mathematics

1 answer:

andrew11 [14]2 years ago

6 0

Answer:

Step-by-step explanation:

we know 100 cm are in one meter, so, 3 meters = 300 cm

then 20/300 = 20 cm of 3 meters , now just reduce the fraction

20/300

= 2 / 30

= 1/15

see??

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30. While making a dessert, Jane used

antiseptic1488 [7]

Answer:

Jane used 2/5 of a scoop more of brown sugar than she did with white sugar.

Step-by-step explanation:

If you want to find how much more something is from something else, you subtract. So, subtract 9/10-1/2. If you want to subtract, they should both have the same denominator. So, 9/10-1/2 is the same as 9/10-5/10. 9/10-5/10 is equal to 4/10 which is simplified to 2/5.

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2 years ago

Point J(2,-3) is reflected across the x-axis, what are the coordinates of new point?

Mkey [24]

Answer:

(2,3)

Step-by-step explanation:

6 0

2 years ago

Show how to to find the product 0.19 times 10 to the power of 3

rosijanka [135]

Answer:

190

Step-by-step explanation:

10x10x10=1000

then multiply 1000 by 0.19

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3 years ago

A ball is thrown into the air and its position is given by h ( t ) = − 6.3 t 2 + 53 t + 24 where h is the height of the ball in

nordsb [41]

Answer:

$h'(t) = -12.6 t +53$

Now we can set up the derivate equal to 0 and we have:

$-12.6 t +53 = 0$

And solving for t we got:

$t = \frac{53}{12.6}= 4.206$

For the second derivate respect the time we got:

$h''(t) = -12.6$

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

$h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft$

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

Step-by-step explanation:

For this case we have the following function:

$h(t) = -6.3t^2 +53 t+24$

In order to maximize this function we need to take the first derivate respect the time and we have:

$h'(t) = -12.6 t +53$

Now we can set up the derivate equal to 0 and we have:

$-12.6 t +53 = 0$

And solving for t we got:

$t = \frac{53}{12.6}= 4.206$

For the second derivate respect the time we got:

$h''(t) = -12.6$

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

$h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft$

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

8 0

3 years ago

3(4x+1)=15? X=<br> What is the solution?

tensa zangetsu [6.8K]

Answer:

x=1

Step-by-step explanation:

3(4x+1)=15

12x+3=15

12x=15-3

12x=12

x=12/12

x=1

3 0

2 years ago