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Nostrana [21]
3 years ago
8

How to rewrite the sum as a product of the GCF of the addends and another number

Mathematics
1 answer:
V125BC [204]3 years ago
8 0

Explanation:

Suppose you have the sum P+Q, and that P and Q have a GCF of g. Then the two terms P and Q can be written as ...

  • P = g·p
  • Q = g·q

Using the distributive property, we can rewrite the sum as ...

  P + Q = g·p +g·q = g(p +q) . . . . . g is the GCF; (p+q) is the other number

_____

<em>Example</em>:

  P = 48 = 8·6

  Q = 40 = 8·5

  g = 8, p=6, q=5

  P + Q = 48 + 40 = 8(6 +5) = 8·11

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3/8, 2/5, 11/20, 23/40, 7/10, 3/4

Step-by-step explanation:

Just change them all to the same denominator and you're good. Put all of the fractions' denominators to 40 as that's the least common denominator. 3/4 turns into 30/40. 2/5 turns into 16/40. 3/8 turns into 15/40. 7/10 turns into 28/40. 11/20 turns into 22/40. And 23/40 stays as it is, because the denominator is already 40.

Putting them in order is now simple,

3/8 (15/40) <  2/5 (16/40) < 11/20 (22/40) < 23/40 < 7/10 (28/40) < 3/4 (30/40)

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