Answer:
There are 3 adult tickets and 7 child tickets
Step-by-step explanation:
You are very close.
Let x = the number of adult tickets
Let y = number of child tickets
24.95x+ 15.95y = 186.50
The total number of tickets is 10
x+y =10
Subtract y from each side
x+y-y = 10-y
x =10-y
Substitute this into the first equation
24.95x+ 15.95y = 186.50
24.95(10-y) +15.95y = 186.50
Distribute
249.5 - 24.95y +15.95y =186.5
Combine like terms
249.5 - 9y = 186.50
Subtract 249.5 from each side
249.5-249.5 - 9y = 186.50-249.5
-9y =-63
Divide each side by -9
-9y/-9 = -63/-9
y =7
Now we need to find x
x+y =10
x+7 =10
Subtract 7 from each side
x+7-7 =10-7
x =3
There are 3 adult tickets and 7 child tickets
The man's transport cost is Rs 4800
Step-by-step explanation:
- Step 1: Given that the amount the man spent on food = Rs 16800 which is 42% of his salary. Form an equation where his salary is x.
42% of x = 16800
42/100 × x = 16800
42x = 1,680,000
x = 1,680,000/42 = Rs 40,000
∴ Salary is Rs 40,000
- Step 2: Calculate the man's transport cost.
12% of 40000 = 12/100 × 40000 = Rs 4800
Answer:
algebra?x9b4
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36, 57, 87
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the answer would be 66 minutes
