How is the water in the swimming pool similar to earth's interior

SAT

2 answers:

Natalka [10]1 year ago

8 0

Explanation:

LenaWriter [7]1 year ago

8 0

my grandparents said because they are are both liquidy and they both have the same thickness.

The deeper you go in both Earth's interior and the swimming pool the greater the pressure grows. The difference is the swimming pool contains, mostly liquid and Earth's interior contains mostly solids. my grandpa said that and my grandma it was wrong so you see which one is right which is what the other kid said so i think my grandpa is right.

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Answer:

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2 years ago

The point (−2,4) lies on the curve in the xy-plane given by the equation f(x)g(y)=17−x−y, where f is a differentiable function o

Nikitich [7]

The value of $\frac{dy}{dx}$ is -3. $\blacksquare$

<h2>Procedure - Differentiability</h2><h3 /><h3>Chain rule and derivatives</h3><h3 />

We derive an expression for $\frac{dy}{dx}$ by means of chain rule and differentiation rule for a product of functions:

$\frac{d}{dx}[f(x)\cdot g(y)] = [f'(x)\cdot \frac{dx}{dx}]\cdot g(y) + f(x) \cdot [g'(y)\cdot \frac{dy}{dx} ]$

$\frac{d}{dx}[f(x)\cdot g(y)] = f'(x)\cdot g(y) +f(x)\cdot g'(y)\cdot \frac{dy}{dx}$ (1)

If we know that $f(x) \cdot g(y) = 17-x-y$ , $f(-2) = 3$ , $f'(-2) = 4$ , $g(4) = 5$ and $g'(4) = 2$ , then we have the following expression:

$-1-\frac{dy}{dx} = (4)\cdot (5) + (3)\cdot (2) \cdot \frac{dy}{dx}$

$-1-\frac{dy}{dx} = 20 + 6\cdot \frac{dy}{dx}$

$7\cdot \frac{dy}{dx} = -21$

$\frac{dy}{dx} = -3$

The value of $\frac{dy}{dx}$ is -3. $\blacksquare$

To learn more on differentiability, we kindly invite to check this verified question: brainly.com/question/24062595

<h3>Remark</h3>

The statement is incomplete and full of mistakes. Complete and corrected form is presented below:

The point (-2, 4) lies on the curve in the xy-plane given by the equation $f(x)\cdot g(y) = 17 - x\cdot y$ , where $f$ is a differentiable function of $x$ and $g$ is a differentiable function of $y$ . Selected values of $f$ , $f'$ , $g$ and $g'$ are given below: $f(-2) = 3$ , $f'(-2) = 4$ , $g(4) = 5$ , $g'(4) = 2$ .