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1 year ago

How did the role of an 'art dealer' change the way artists decided what to paint?.

1 answer:

5 0

It should be noted that the role of an 'art dealer' change the way artists decided what to paint in the sense that the dealer was now the one leading the artists in what is popular to create.

This helps to Change things in the industry, because way artists decided what to paint changed as a result of demand from the dealers.

<h3>Who is an art dealer?</h3>

An art dealer can be described as a highly specialized person or company that base on buying and selling of arts.

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Which of the following best illustrates the relationship between entities and attributes

Lelechka [254]

A statement which best illustrates the relationship between entities and attributes is: B) the entity CUSTOMER with the attribute PURCHASE.

<h3>What is an entity relationship?</h3>

An entity relationship can be defined as a data model with the highest level of abstraction and it is typically designed and develop to avail designers or programmers (end users) an ability to use a graphical tool to examine structures rather than describe them by using text.

<h3>What is an attribute?</h3>

In Computer technology, an attribute can be defined as a unique characteristic or quality which primarily describes an entity in a software program.

In this context, we can infer and logically deduce that a statement which best illustrates or shows the relationship between entities and attributes is the entity "CUSTOMER" with the attribute "PURCHASE."

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Complete Question:

Which of the following best illustrates the relationship between entities and attributes?

A)the entity CUSTOMER with the attribute PRODUCT

B)the entity CUSTOMER with the attribute PURCHASE

C)the entity PRODUCT with the attribute PURCHASE

D)the entity product with the attribute CUSTOMER

3 0

1 year ago

Why is Zaroff particularly happy to have Rainsford as a guest? Question 2 options: Zaroff is curious to hear stories of Rainsfor

irinina [24]

Zaroff is glad to meet another expert hunter.

8 0

2 years ago

Which of the following is not a component of your high school transcripts?

Marina CMI [18]

I think the answer is A

4 0

2 years ago

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the volumes of two similar solids are 210 m3 and 1,680 m3. the surface area of the larger solid is 856 m2. what is the surface a

kolezko [41]

The surface area of the smaller solid is found to be 214 square meters.

<h3>What is Surface area?</h3>

The surface area is given as the sum of the area of all the faces of a three-dimensional object.

The same shape has equivalent ratio of the surface area to volume. It is given as:

$\rm \dfrac{\sqrt{area_1}}{\sqrt{area_2}}=\dfrac{\sqrt[3]{Volume_1} }{\sqrt[3]{Volume_2} }$

On considering the power of 6 at both the sides of the equation:

$\rm \dfrac{area_1^2}{area_2^2}=\dfrac{volume_1}{volume_2}$

Considering area 1 and volume 1 for the larger solid, and area 2 and volume 2 for the smaller solid, substituting the values give:

$\rm\dfrac{(856\;m^2)^3}{(area_^2)^3}=\dfrac{(1680\;m^3)^2}{(210\;m^3)^2}$

By solving the above equation, the area of the smaller solid is found as 214 square meters. Thus, option B is correct.

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6 0

1 year ago

company manufactured six television sets on a given day, and these TV sets were inspected for being good or defective. The resul

lana [24]

Sampling distribution involves the proportions of a data element in a given sample.

<em>The proportion of Good TV set is 0.67</em>
<em>The number of ways of selecting 5 from 6 TV sets is 6</em>
<em>The number of ways of selecting 4 from 6 TV sets is 15</em>

<em />

Given

$n = 6$

Sample Space = Good, Good, Defective, Defective, Good, Good

<u>(a) Proportion that are good</u>

From the sample space, we have:

$Good = 4$

So, the proportion (p) that are good are:

$p = \frac{Good}{n}$

$p = \frac{4}{6}$

$p = 0.67$

<u>(b) Ways to select 5 samples (without replacement)</u>

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 5$

So, we have:

$^6C_5 = \frac{6!}{(6 - 5)!5!}$

$^6C_5 = \frac{6!}{1!5!}$

$^6C_5 = \frac{6 \times 5!}{1 \times 5!}$

$^6C_5 = \frac{6}{1}$

$^6C_5 = 6$

Hence, there are 6 ways

<u>(c) All possible sample space of 4</u>

First, we calculate the number of ways to select 4.

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 4$

So, we have:

$^6C_4 = \frac{6!}{(6 - 4)!4!}$

$^6C_4 = \frac{6!}{2!4!}$

$^6C_4 = \frac{6 \times 5 \times 4}{2 \times 1 \times 4!}$

$^6C_4 = \frac{30}{2}$

$^6C_4 = 15$

So, the table is as follows:

$\left[\begin{array}{ccc}TV&Good&Proportion\\1,2,3,4&2&0.5&2,3,4,5&2&0.5&3,4,5,6&2&0.5\\4,5,6,1&3&0.75&5,6,1,2&4&1&6,1,2,3&3&0.75\\1,2,3,5&3&0.75&3,5,6,2&3&0.75&1,3,4,5&2&0.5\\1,3,4,6&2&0.5&1,4,5,2&3&0.75&2,4,6,1&3&0.75\\2,4,6,3&2&0.5&2,4,6,5&3&0.75&3,5,6,1&3&0.75\end{array}\right]$

The proportion column is calculated by dividing the number of Good TVs by the total selected (4) i.e.

$p = \frac{Good}{n}$

<u>(d) The sampling distribution</u>

In (a), we have:

$p = 0.67$ --- proportion of Good TV

The sampling error is calculated as follows:

$SE_n = |p - p_n|$

So, we have:

$\left[\begin{array}{ccc}TV&Good&SE\\1,2,3,4&2&0.17&2,3,4,5&2&0.17&3,4,5,6&2&0.17\\4,5,6,1&3&0.08&5,6,1,2&4&0.33&6,1,2,3&3&0.08\\1,2,3,5&3&0.08&3,5,6,2&3&0.08&1,3,4,5&2&0.17\\1,3,4,6&2&0.17&1,4,5,2&3&0.08&2,4,6,1&3&0.08\\2,4,6,3&2&0.17&2,4,6,5&3&0.08&3,5,6,1&3&0.08\end{array}\right]$

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3 0

2 years ago