It’s a prediction so basically an estimate of how much students he thought were going to be there. An actual number is the real total.
Ok, first let's multiply:
3 x 1/6 = 3/6 (simplify:) 1/2
Then multiply again:
3 x 1/9 = 3/9 (simplify:) 1/3
Now the expression is simplified to (1/2x, 1/2y)
Hope this helped! Please comment or DM me if you have anymore questions or don't understand :)
Answer:
Are you sure it ia not x2 - x1 in the denominator?
Best is to draw a sketch of the three points.
Next step is to find the distances BC, CD, DB.
The perimeter is the sum of the three distances.
The distances are found using the distance formula:
D=sqrt((y2-y1)^2+(x2-x1)^2)
order of (x1,y1), (x2,y2) is not important.
BC=sqrt((3- -3)^2+(5-3)^2)=sqrt(6^2+2^2)=sqrt(40)=5.324
CD=sqrt((-1-3)^2+(0-5)^2)=sqrt(4^2+5^2)=sqrt(41)=6.403
DB=sqrt((-3- -1)^2+(3-0)^2)=sqrt(2^2+3^2)=sqrt(13)=3.606
So perimeter = BC+CD+DB=16.333 (approximately)
Answer:
y = -3/2x + 11
Step-by-step explanation:
2x - 3y = 21 => 3y = 2x - 21 => y = 2/3x - 7
Perpendicular lines have slopes that are negative reciprocals of one another
so slope of perpendicular line is -3/2
y = mx + b
y = -3/2x + b
Using (2,8)
8 = -3/2(2) + b
8 = -3 + b
b = 11
y = -3/2x + 11
