First step, i would try to figure out the slope. think of it as a typical y=mx+b linear equation as you check out the graph.
it's just rise over run (rise up this many, run over that many), and your options are (-2/3) or (-3/2)
start at the y-intercept, which is just above the middle of the graph. if you go down 2 and try to go over 3, you hit the line before you can count 3 units. that means this slope is incorrect.
go back to the y-intercept. down 3, over 2--there you go. your slope here is (-3/2), which immediately gets rid of half your answer choices for having the wrong slope
the next thing you have to do is decide <em>where</em> this graph should be shaded. the shaded region shows the domain; the white region shows what's outside of your domain. this inequality is shaded "below" which means that the y values are LESS than "(-3/2)x +1"
that eliminates another one of your answer choices; choice 3 is correct. the inequality is y < (-3/2)x + 1
if the graphs of inequalities are shaded below and the line is dotted, it's less than. if the graphs of inequalities are shaded above and the line is dotted, it's greater than. general rules for ya
D, because two negative signs next to each other means to add so its pretty much 7/8+1/8 which equals 8/8 which also equals 1
Answer:
<em>The probability that the second ball is red is 71%</em>
Step-by-step explanation:
<u>Probabilities</u>
We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).
The first ball can be red (R) or green (G). The probability that it's red is computed by
The probability is's green is computed by
If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is
If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is
The total probability of the second ball being red is
The probability that the second ball is red is 71%
Answer:
5x-6y-12=0
Step-by-step explanation:
...make y the subject y=-6/5x +2
...use the coefficient of x as the gradient,m=-6/5
...for a perpendicular line,find the negative reciprocal of the gradient,5/6
...sub into the eqn y= -1/m(x-a)+b
