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notka56 [123]
3 years ago
13

Could a quadrilateral have 4 obtuse angles?

Mathematics
2 answers:
kupik [55]3 years ago
6 0
Yes. As long as the shape has 4 sides, it's a quadrilateral.
Svet_ta [14]3 years ago
5 0
No because a quadrilateral can only add up to 360 degrees.
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What is a system of equation?
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SYSTEMS OF EQUATIONS. A system of equations is a collection of two or more equations with a same set of unknowns. In solving a system of equations, we try to find values for each of the unknowns that will satisfy every equation in the system.
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Jamie has 2/3 inches of rope. molly has 6/9 inches of rope who has more
mel-nik [20]

Answer:

Step-by-step explanation:

They have the same amount

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3 years ago
Carlos drove to the train station and back. The trip there took five hours and the trip back took four hours. What was Carlos' a
katrin2010 [14]

Answer: 54.4 mph

Step-by-step explanation:

First find the distance to the train station. If it took Carlos 4 hours to come back driving at 68 mph, the distance is:

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This means that Carlos drove for 5 hours to cover 272 miles the first time. His average speed was therefore:

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3 years ago
Help pLEASE! be sure its right!!
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5 0
3 years ago
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How do you do this question?
Alex Ar [27]

Step-by-step explanation:

(a) dP/dt = kP (1 − P/L)

L is the carrying capacity (20 billion = 20,000 million).

Since P₀ is small compared to L, we can approximate the initial rate as:

(dP/dt)₀ ≈ kP₀

Using the maximum birth rate and death rate, the initial growth rate is 40 mil/year − 20 mil/year = 20 mil/year.

20 = k (6,100)

k = 1/305

dP/dt = 1/305 P (1 − (P/20,000))

(b) P(t) = 20,000 / (1 + Ce^(-t/305))

6,100 = 20,000 / (1 + C)

C = 2.279

P(t) = 20,000 / (1 + 2.279e^(-t/305))

P(10) = 20,000 / (1 + 2.279e^(-10/305))

P(10) = 6240 million

P(10) = 6.24 billion

This is less than the actual population of 6.9 billion.

(c) P(100) = 20,000 / (1 + 2.279e^(-100/305))

P(100) = 7570 million = 7.57 billion

P(600) = 20,000 / (1 + 2.279e^(-600/305))

P(600) = 15170 million = 15.17 billion

7 0
3 years ago
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