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1 year ago

Estimate the quotient of 68)6080 Express any remainder beginning with an R.

Mathematics

2 answers:

ratelena [41]1 year ago

8 0

The answer in decimals is 89.4117647059

Your final estimated answer is 89 R 28
(aka 89, 28 Remainder)

Contact [7]1 year ago

4 0

89 R 28 is the answer to your question

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Can someone explain to me how to do this please

castortr0y [4]

Answer:

look at the attachment (p.s you could also use desmos to find the vertex)

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3 years ago

Multiply and simplify. 2x4yx⋅6xy2z3

OLEGan [10]

Answer:

The given expression $2x^4yx \times 6xy^2z^3$ on multiplying is $12x^6y^3z^3$

Step-by-step explanation:

Consider the given two expressions $2x^4yx$ and $6xy^2z^3$

We have multiply both expressions,

$2x^4yx \times 6xy^2z^3$

To multiply two terms first multiply constant numbers that is 6 × 2 = 12

For x , y and z apply property of exponent,

$x^a\cdot x^b=x^{a+b}$

Then power of x together will be,

$x^4\cdot x\cdot x=x^{4+1+1}=x^6$

Similarly for y powers,

$y \cdot y^2=y^{1+2}=y^3$

Since first term do not have any expression for z so it will remain same.

Thus, the given expression on multiplying become,

$2x^4yx \times 6xy^2z^3$ is $12x^6y^3z^3$

7 0

3 years ago

Read 2 more answers

Solve the following (^ this sign symbolizes the power) 7). 4^2 8). 7^2 9). 6^4 10). 1^2 11) 5^3 12) 1^3

Alchen [17]

Answer:

7. 4^2 = 6

8. 7^2 = 49

9. 6^4 =1296

10. 1^2 = 1

11. 5^3 =125

12. 1^3 =1

Step-by-step explanation:

8 0

3 years ago

Find the value of x. Plz help I don’t understand

coldgirl [10]

The answer for this problem is 125

4 0

3 years ago

Read 2 more answers

The amounts a soft drink machine is designed to dispense for each drink are normally distributed, with a mean of 12.1 fluid ounc

Ludmilka [50]

Answer:

$\mu = 12.1\\\sigma = 0.3$

a) Find the probability that the drink is less than 11.9 fluid ounces

We are supposed to find P(x<11.9)

x= 11.9

We will use z score formula :

$z=\frac{x-\mu}{\sigma}$

$z=\frac{11.9-12.1}{0.3}$

$z=-0.67$

Refer the z table

So, P(z<-0.67) = 0.2514

Hence the probability that the drink is less than 11.9 fluid ounces is 0.2514

b)Find the probability that the drink is between 11.6 and 11.9 fluid ounces

x= 11.6

We will use z score formula :

$z=\frac{x-\mu}{\sigma}$

$z=\frac{11.6-12.1}{0.3}$

$z=-1.67$

x= 11.9

We will use z score formula :

$z=\frac{x-\mu}{\sigma}$

$z=\frac{11.9-12.1}{0.3}$

$z=-0.67$

We are supposed to find P(11.6<x<11.9)

So, P(11.6<x<11.9)= P(x<11.9)-P(x<11.6)

P(-1.67<z<-0.67)= P(z<-0.67)-P(z<-1.67)

Refer the z table

P(-1.67<z<-0.67)= P(z<-0.67)-P(z<-1.67)

P(-1.67<z<-0.67)= 0.2514-0.0475

P(-1.67<z<-0.67)= 0.2039

So, the probability that the drink is between 11.6 and 11.9 fluid ounces is 0.2039.

c)Find the probability that the drink is more than 12.6 fluid ounces

We are supposed to find P(x>12.6)

x= 12.6

We will use z score formula :

$z=\frac{x-\mu}{\sigma}$

$z=\frac{12.6-12.1}{0.3}$

$z=1.67$

Refer the z table

P(x>12.6)=1-P(x<12.6)

P(z>1.67)=1-P(z<1.67)

P(z>1.67)=1-0.9525

P(z>1.67)=0.0475

Hence the probability that the drink is more than 12.6 fluid ounces is 0.0475

d) Is the drink containing more than 12.6 fluid ounces an unusual event?

Since p value is less than alpha (0.05)

Answer = No, because the probability that a drink containing more than 12.6 fluid ounces is less than 0.05, this event is not unusual.

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3 years ago