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seropon [69]
2 years ago
8

What is the correct answer NEED ASAP PLEASE ​

Mathematics
1 answer:
Rudik [331]2 years ago
8 0

Answer:

1 solution

Step-by-step explanation:

x^2 - 14x + 49 = 0

Factor the expression:

                 x     -     7

           ------------------------

  x       |    x^2   |    - 7x   |

  -        ------------------------

  7       |   - 7x    |    49     |

            ------------------------

(x - 7)^2 = 0

x - 7 = 0

x = 7

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Please help I don’t know how to do this
mina [271]

Answer:

f(x) = -2x + 7, when x > 1

f(x) = 4x + 1 when x ≤ 1

Step-by-step explanation:

The right side graph passe through points (1,5) and (2,3).  

Hence, the equation of the line  

\frac{y - 5}{5 - 3} = \frac{x - 1}{1 - 2}

⇒ (y - 5) = 2(1 - x)

⇒ y - 5 = 2 - 2x

⇒ y = -2x +7.......... (1)

Now, the left side graph passes through points (1,5) and (0,1)

Therefore, the equation of the graph will be  

\frac{y - 5}{5 - 1} = \frac{x - 1}{1 - 0}

⇒ y - 5 = 4(x - 1)

⇒ y = 4x + 1 ........ (2)

Hence, the equation (1) gives the function in the right side of the given graph which does not include the point (1,5) and extends to the right from this point.

Therefore, f(x) = -2x + 7, when x > 1 (Answer)

Again, equation (2) gives the function in the left side of the given graph which includes the point (1,5) and extends to the left from this point.

Therefore, f(x) = 4x + 1 when x ≤ 1 (Answer)

5 0
3 years ago
Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?
Phantasy [73]

Answer:

\cos (a-b)=\cos a \cos b+\sin a \sin b

Step-by-step explanation:

 Given : \cos (180^{\circ}-q)=-\cos q

We have to write which identity we will use to prove the given statement.

Consider \cos (180^{\circ}-q)=-\cos q

Take left hand side of given expression \cos (180^{\circ}-q)

We know

\cos (a-b)=\cos a \cos b+\sin a \sin b

Comparing , we get, a= 180° and b = q

Substitute , we get,

\cos (180^{\circ}-q)=\cos 180^{\circ}  \cos (q)+\sin q \sin 180^{\circ}

Also, we know \sin 180^{\circ}=0 and \cos 180^{\circ}=-1

Substitute, we get,

\cos (180^{\circ}-q)=-1\cdot \cos (q)+\sin q \cdot 0

Simplify , we get,

\cos (180^{\circ}-q)=-\cos (q)

Hence, use difference identity to  prove the given result.

7 0
3 years ago
Read 2 more answers
I leave good reviews
Illusion [34]

Answer:

I am so not good at math at all

3 0
3 years ago
What equation is ALWAYS TRUE?<br> HELPPPPPP
nadezda [96]

Answer:

2(x-1)=2x-2

Step-by-step explanation:

distribute the 2 into (x-1) so you get 2x-2 which is equal to 2x-2

3 0
3 years ago
I will be taking an algebra test unit 3.12.3
Nonamiya [84]

OKay i willl help what are the questions


4 0
3 years ago
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