Answer with Step-by-step explanation:
We are given that
and
are linearly independent.
By definition of linear independent there exits three scalar
and
such that
![a_1x_1+a_2x_2+a_3x_3=0](https://tex.z-dn.net/?f=a_1x_1%2Ba_2x_2%2Ba_3x_3%3D0)
Where ![a_1=a_2=a_3=0](https://tex.z-dn.net/?f=a_1%3Da_2%3Da_3%3D0)
![y_1=x_2+x_1,y_2=x_3+x_2,y_3=x_3+x_1](https://tex.z-dn.net/?f=y_1%3Dx_2%2Bx_1%2Cy_2%3Dx_3%2Bx_2%2Cy_3%3Dx_3%2Bx_1)
We have to prove that
and
are linearly independent.
Let
and
such that
![b_1y_1+b_2y_2+b_3y_3=0](https://tex.z-dn.net/?f=b_1y_1%2Bb_2y_2%2Bb_3y_3%3D0)
![b_1(x_2+x_1)+b_2(x_3+x_2)+b_3(x_3+x_1)=0](https://tex.z-dn.net/?f=b_1%28x_2%2Bx_1%29%2Bb_2%28x_3%2Bx_2%29%2Bb_3%28x_3%2Bx_1%29%3D0)
![b_1x_2+b_1x_1+b_2x_3+b_2x_2+b_3x_3+b_3x_1=0](https://tex.z-dn.net/?f=b_1x_2%2Bb_1x_1%2Bb_2x_3%2Bb_2x_2%2Bb_3x_3%2Bb_3x_1%3D0)
![(b_1+b_3)x_1+(b_2+b_1)x_2+(b_2+b_3)x_3=0](https://tex.z-dn.net/?f=%28b_1%2Bb_3%29x_1%2B%28b_2%2Bb_1%29x_2%2B%28b_2%2Bb_3%29x_3%3D0)
![b_1+b_3=0](https://tex.z-dn.net/?f=b_1%2Bb_3%3D0)
...(1)
![b_1+b_2=0](https://tex.z-dn.net/?f=b_1%2Bb_2%3D0)
..(2)
![b_2+b_3=0](https://tex.z-dn.net/?f=b_2%2Bb_3%3D0)
..(3)
Because
and
are linearly independent.
From equation (1) and (3)
...(4)
Adding equation (2) and (4)
![2b_1==0](https://tex.z-dn.net/?f=2b_1%3D%3D0)
![b_1=0](https://tex.z-dn.net/?f=b_1%3D0)
From equation (1) and (2)
![b_3=0,b_2=0,b_3=0](https://tex.z-dn.net/?f=b_3%3D0%2Cb_2%3D0%2Cb_3%3D0)
Hence,
and
area linearly independent.
Answer:
1)1/3
2)3
Step-by-step explanation:
rise over run then reduce
The domain is t=0 to t=3.2 and range is y = 0 to 57.125 feet.
<u>What are Domain and range of a Function?</u>
- The range of values that we are permitted to enter into our function is known as the domain of a function.
- The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input.
- After we enter an x value, the function outputs this sequence of values. The y values are those.
- A function can be compared to a piece of equipment on an assembly line.
- A few screws and nuts are located on one end of the assembly line, while a car is located on the other. The function is the device in the center. The domain is the screws and bolts that we insert into the machine. The car at the other can be thought of as the range.
Given function is : y = -16t^2 + 50t + 4
It hits the ground when y=0
0 = -16t^2 + 50t + 4
8t^2 -25t -2 = 0
t = 25/16 + (1/16)sqrt(625+64) = (25+26.25)/16 = 51.25/16 = 3.2 seconds
domain is t=0 to t=3.2 [3.2]
take the derivative and set it equal to zero to find maximum height
-32t +50 = 0
t = 50/32 = 25/16 = 1.5625 seconds
-16(25/16) + 50(25/16) + 4 = 34(25/16) + 64/16 = (17(25)+32)/8 = 57.125 = maximum height
range is y = 0 to 57.125 feet. the discus goes from 4 feet to 57 1/8 feet and back down to 0 feet.
Know more about Domain and Range with the help of the given link:
brainly.com/question/20349151
#SPJ4
Lets start with the chain of 3's:
18 = 3 + 3 + 3 + 3 + 3 + 3
But, we know that
3 + 3 = 2 + 2 + 2
Sol, let's replace 3 + 3 by 2 + 2 + 2 one by one.
Hence, the possible ways of combinations are listed below:
18 = 3 + 3 + 3 + 3 + 2 + 2 + 2 (1)
18 = 3 + 3 + 2 + 2 + 2 + 2 + 2 + 2 (2)
Therefore, there are two combinations of 2- and 3- point shots that could total 18 points.
![\frac{-7}{12} = \frac{y}{-36}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-7%7D%7B12%7D%20%3D%20%5Cfrac%7By%7D%7B-36%7D%20)
First, simplify
![\frac{y}{-36}](https://tex.z-dn.net/?f=%20%5Cfrac%7By%7D%7B-36%7D%20)
to
![- \frac{y}{36}](https://tex.z-dn.net/?f=-%20%5Cfrac%7By%7D%7B36%7D%20)
/ Your problem should look like:
Second, multiply both sides by 36. / Your problem should look like:
Third, multiply both sides by -1. / Your problem should look like:
Fourth, switch your sides. / Your problem should look like:
![y = 21](https://tex.z-dn.net/?f=y%20%3D%2021)
Answer:
C) 21