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Xelga [282]
3 years ago
7

What is the y-intercept of the equation: 3x+6y=42

Mathematics
1 answer:
Dafna1 [17]3 years ago
3 0
The y intercept is y=7-x/2
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HELP PLEASE ! TRUE OR FALSE ?!
miss Akunina [59]
This is false because on 2) x does not equal 3. 
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Jada have a monthly budget for her cell phone bill last month she spent 120% of her budget and the bill was $60 what is Jada mon
Damm [24]

Assume that the budget is n.

Now we are given that 120% of the budget is equal to $60.

This means that:

60 = 1.2n

Solve the equation for n to know the budget:

60 = 1.2n

n = 60 / 1.2 = 50

Based on the above calculations, Jada's budget is 50$

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Is 2,107,954 even or odd
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Answer:

Even

Step-by-step explanation:

Ends in 4

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Joe answered 18 questions correct on his science test the test had 45 questions what percent did joe answer correctly.
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3 years ago
Solve each trigonometric equation such that 0 ≤ x ≤ 2????. Round answers to three decimal places.
zlopas [31]

Answer:

a) x= arccos(3/5) = 0.927

Just one solution

b) cos(x) = -\frac{5}{3}

But we know that the cosine can't be negative so then this equation no have solutions on the reals.

c) x = arcsin(\frac{1}{3})=0.3398

This is only the solution on the interval assumed.

d) x= -0.1145

Step-by-step explanation:

a. 5 cos(x) − 3 = 0

For this case we can do this:

5 cos(x) = 3

Now we can divide both sides by 5 and we got:

cos (x) = \frac{3}{5}

If we apply arccos on both sides we got:

x = arccos (\frac{3}{5})+2\pi n, x=2\pi-arccos (\frac{3}{5})+2\pi n

So for this case the possible solution is:

x= arccos(3/5) = 0.927

Just one solution. This is only the solution on the interval assumed.

b. 3 cos(x) + 5 = 0

We can do this:

3 cos (x) = -5

Then we can divide by 3 both sides and we got:

cos(x) = -\frac{5}{3}

But we know that the cosine can't be negative so then this equation no have solutions on the reals.

c. 3 sin(x) − 1 = 0

We can do this:

3 sin(x) = 1

Then we can divide both sides by 3 and we got:

sin(x) = \frac{1}{3}

The general solutions would be:

x = arcsin(\frac{1}{3}) + 2\pi n , x= \pi -arcsin (\frac{1}{3}) + 2\pi n

x = arcsin(\frac{1}{3})=0.3398

This is only the solution on the interval assumed.

d. tan(x) = −0.115

For this case we can solve the value of x like this:

x = arctan(-0.115) +\pi n

And then the only possible solution for this case is:

x= -0.1145

3 0
4 years ago
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