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2 years ago

Measure of Variability:

1 answer:

7 0

The mean absolute deviation shows the average distance number data is from each other. The bigger it is the farther the numbers are away from each other and vice versa.

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Evaluate the expression

andreev551 [17]

Step-by-step explanation:

this is correct answer thank you

3 0

3 years ago

X-3y=2 what is the slope

Brums [2.3K]

1/3 is the slope.
x-3y=2
-3y=-x+2
y=(1/3)x+2/3

3 0

3 years ago

How do you solve this equation 2x+5y=11 -3x+8y=-1

Brums [2.3K]

5y=3x...............

4 0

3 years ago

If y varies inversely as x and y = 27 when x = 12 , find x when y = - 9 .

Sergio039 [100]

Answer:

x = - 36

Step-by-step explanation:

Given that y varies inversely as x then the equation relating them is

y = $\frac{k}{x}$ ← k is the constant of variation

To find k use the condition y = 27 when x = 12, then

k = yx = 27 × 12 = 324, thus

y = $\frac{324}{x}$ ← is the equation of variation

When y = - 9, then

- 9 = $\frac{324}{x}$ ( multiply both sides by x )

- 9x = 324 ( divide both sides by - 9 )

x = - 36

3 0

3 years ago

Which expression is equivalent to (4x^(3)y^(5))(3x^(5)y)^(2)

marshall27 [118]

Answer:

$(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7$

Step-by-step explanation:

Given

$(4x^3y^5)(3x^5y)^2$

Required

The equivalent expression

We have:

$(4x^3y^5)(3x^5y)^2$

Expand

$(4x^3y^5)(3x^5y)^2 = 4x^3y^5*9x^{10}y^2$

Further expand

$(4x^3y^5)(3x^5y)^2 = 4*9*x^3*x^{10}y^5*y^2$

Apply laws of indices

$(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7$

8 0

3 years ago