P-.15p this is the expression for cost after discount
and its just .15p for just the discount
Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
They are 1 and 3!
Hope this helped! :)
X = 7
y = 10
x + y = 700
7x + 10y = 6400
10x + 10y = 7000
(-) 7x + 10y = 6400
______________
3x = 600
x = 200
200 + y = 700
y = 500
The answer is 10.6 oz.
2.65 / 0.25 = 10.6
Hope this helps! If so, please mark brainliest!
