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AVprozaik [17]
2 years ago
5

Write the equation of the line in slope intercept form Slope=-4 Point=(2,-4)

Mathematics
2 answers:
liq [111]2 years ago
7 0
Y=2x-8 would be your answer
Andrei [34K]2 years ago
5 0

Answer:

y=2x-8

or

f(x)=2x-8

Step-by-step explanation:

To write in slope-intercept form using this information, first use the point slope formula.

y-y1=m(x-x1)

m is slope.

y+4=2(x-2)

Use distributive property on the right side.

y+4=2x-4

Now, subtract 4 from both sides.

y+4-4=2x-4-4

y=2x-8

Written using function notation:

f(x)=2x-8

Hope this helps!

If not, I am sorry.

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The following integral requires a preliminary step such as long division or a change of variables before using the method of par
shtirl [24]

Division yields

\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}

Now for partial fractions: you're looking for constants <em>a</em>, <em>b</em>, and <em>c</em> such that

\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}

\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a

which gives <em>a</em> + <em>b</em> = 2, <em>c</em> = 0, and 2<em>a</em> = -7, so that <em>a</em> = -7/2 and <em>b</em> = 11/2. Then

\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}

Now, in the integral we get

\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx

The first two terms are trivial to integrate. For the third, substitute <em>y</em> = <em>x</em> ² + 2 and d<em>y</em> = 2<em>x</em> d<em>x</em> to get

\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}

7 0
3 years ago
Applied to the graph
lana [24]

Answer:

Using the graph of f(x) and g(x), where g(x) = f(kx), determine the value of k. A: 4 B: 1/4 C:-1/4 D:-4 "

Step-by-step explanation:

7 0
3 years ago
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