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crimeas [40]
2 years ago
9

Item 5

Mathematics
1 answer:
zvonat [6]2 years ago
7 0

Answer:

The answe would be "All parallelogram are quadrilaterals."

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A quality control specialist for a restaurant chain takes a random sample of size 12 to check the amount of soda served in the 1
Sloan [31]

Answer:

The answer is E. Impossible to determine

Step-by-step explanation:

Normally, you would find the Confidence interval of a normal sample by using

X(-+) Z* Sigma/n

Where x is the mean, sigma the standard deviation n the size of the sample and z the value  determined by your confidence interval size of 95%

.However, this approximation of a confidence interval may only be used for a sample if the number of observations is at least 30 or above.  When we have less observations than 30 we must use the standard deviation of the populations. But we only have a sample standard deviation so its not adequate or possible to determine CI the true mean of the population with such a small sample size.

3 0
4 years ago
For the given equation, y = 4(x) - 1, what is the value of y for x = 2?
Alik [6]

Answer:

The answer is D (7).

Step-by-step explanation:

If you plug in 2 where x is, you get 4*2 -1, which is 8-1, which equals to 7.

3 0
4 years ago
Read 2 more answers
Please answer this ASAP
stellarik [79]

9514 1404 393

Explanation:

1. ∠BAC ≅ ∠BCA, BD ≅ BE, ∆BDA and ∆BEC are right triangles . . . . given

2. ∆ABC is isosceles . . . . definition of isosceles triangle

3. BA ≅ BC . . . . definition of isosceles triangle

4. ∆BDA ≅ ∆BEC . . . . HL theorem

5. AC ≅ CE . . . . CPCTC

4 0
3 years ago
Two jugs are similar. The smaller jug has radius 4cm and the bigger jug has radius
ivolga24 [154]

Given:

Two jugs are similar. The smaller jug has radius 4 cm and the bigger jug has radius 6 cm and surface area 125 cm².

To find:

The area of the smaller jug.

Solution:

If two figures are similar, then the ratio of their areas is proportional to the square of the corresponding sides of the figures.

Two jugs are similar. So,

\dfrac{\text{Area of smaller jug}}{\text{Area of bigger jug}}=\dfrac{(\text{Radius of smaller jug})^2}{(\text{Radius of bigger jug})^2}

\dfrac{\text{Area of smaller jug}}{125}=\dfrac{(4)^2}{(6)^2}

\dfrac{\text{Area of smaller jug}}{125}=\dfrac{16}{36}

\text{Area of smaller jug}=\dfrac{4}{9}\times 125

\text{Area of smaller jug}\approx 55.56

Therefore, the area of the smaller jug is about 55.56 cm².

6 0
3 years ago
Read 2 more answers
What equation is equivalent to P = mgh, but solved for Y? **please explain**
Elan Coil [88]
Potential energy = mass * acceleration due to gravity (9.8m/s^2) * height

P = mgh
P/mg = mgh/mg
P/mg = h
7 0
3 years ago
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