Answer:

Step-by-step explanation:
The formula of an area of a parallelogram:

b - base
h - height
We have:
base₁ = 9.8 in
base₂ = 10 in
height₁ = 5.6 in
height₂ = h
The area of a parallelogram:
and 
Therefore we have the equation:

Substitute:

<em>divide both sides by 10</em>

<h2>
Answer:</h2>

<h2>
Step-by-step explanation:</h2>
We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:
Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

Step 4: solve for z, then for y, then for x:


By substituting
into the first equation, we get the
. So:

1. Answer is 14.
you first do 8x6 cause of BEDMAS, which is 48. then subtract 12, which gives you 36. then subtract 36 from 50 because 50 is the total amount it should be on both sides.
50 - 36 = 14
2. Answer is 8
5x3 is 15, + 2 is 17. then 20 - 17 gives you 3. you then have 24 divided by a number, and that number is 8 because 24 divided by 8 gives you three