Answer:
C. -5
The slope is -5.
Step-by-step explanation:
Hope this helps! :)
They've given me two categories of things: assessed values of properties, and the amounts of taxes paid. My ratios will then use these two categories. I will set up my ratios with the assessed valuation on top (because that's what I read first in the exercise), and I will use "v" to stand for the value that I need to find.
value
tax
:
70,000
1,100
=
v
1,400
tax
value
:
1,100
70,000
=
1,400
v
I'll use the shortcut method for solving, multiplying the 70,000 and the 1,400 in one direction, and then dividing by the 1,100 going in the other direction:
70,000 / 1,100 = v / 1,400; multiplying gives (70,000)(1,400); dividing gives v = [(70,000)(1,400)]/1,100
v
=
(
70,000
)
(
1,400
)
1,100
v=
1,100
(70,000)(1,400)
v
=
98,000,000
1,100
v=
1,100
98,000,000
v
=
89,090.9090909...
v=89,090.9090909...
Since the solution is a dollars-and-cents value, I must round the final answer to two decimal places; the "exact" form (whether repeating decimal or fraction) wouldn't make sense in this context. So my answer is: $ 89.090.91
Answer:
Yes, the normal curve can be used as an approximation to the binomial probability.
Step-by-step explanation:
Let <em>X</em> = number of students that pass their college placement exam.
The probability that a given student will pass their college placement exam is, P (X) = <em>p</em> = 0.53.
A random sample of <em>n</em> = 127 students is selected.
The random variable <em>X</em> follows a Binomial distribution.
But the sample size is too large.
A Normal approximation to Binomial can be used to approximate the distribution of proportion <em>p</em>.
The conditions to be satisfied are:
- <em>np</em> ≥ 10
- <em>n</em>(1-<em>p</em>) ≥ 10
Check whether the conditions are satisfied as follows:
Both he conditions are satisfied.
Thus, a normal curve can be used as an approximation to the binomial probability.
What exactly is ur question? This is just a statement