Answer:
Length: 5 ft; width: 4 ft.
Step-by-step explanation:
A = LW formula for area of rectangle
(2x + 1)(2x) = 20 substitute length, width, and area into formula
4x² + 2x - 20 = 0 use the distributive property to multiply out left side
2x² + x - 10 = 0 divide both sides of equation by 2
(2x + 5)(x - 2) = 0 factor out trinomial
2x + 5 = 0 or x - 2 = 0 use zero product rule to solve for x
2x = -5 or x = 2 subtract 5 from both sides; add 2 to both sides
x = -5/2 or x = 2
We discard x = -5/2 since it would give negative length and width, and the length and width cannot be negative.
Length: 2x + 1 = 2(2) + 1 = 5
Width: 2x = 2(2) = 4
Length: 5 ft; width: 4 ft.
9.50 + (2.20)r
For example if he fixed 3 watches
9.50 + (2.20)3
We plug in 3 for r and he makes 6.60 extra.
<span>1. multiply to -18
add to -17 = Multiplying -18 and 1 will give -18 as the result and then on
adding -18 and + 1 the result comes to -17
</span><span>2. multiply to 36 add
to -13 = Multiplying -9 and -4 will give -36 as the result and then on
adding -9 and -4 the result comes to -13
</span><span>3. multiply to -24 add to -5<span>= </span></span><span>Multiplying -8 and +3 will give -24 as the result and then on
adding -8 and +3 the result comes to -5
4. multiply to -18 add to 7= </span><span>Multiplying +9 and -2 will give -18 as the result and then on
adding +9 and -2 the result comes to 7
5. multiply to -36 add to 9= </span><span><span>Multiplying +12 and -3 will give -36 as the result and then on
adding +12 and -3 the result comes to 9
</span> 6. multiply to 24 add to 10= </span><span><span>Multiplying +6 and +4 will give 24 as the result and then on
adding +6 and +4 the result comes to 10
</span> 7. multiply to 18 add to -9= </span><span><span><span>Multiplying -6 and -3 will give -18 as the result and then on
adding -6 and -3 the result comes to -9
</span> 8. multiply to -36 add to -16</span>= </span><span>Multiplying -18 and +2 will give -36 as the result and then on
adding -18 and +2 the result comes to -16</span>
Answer:
I think the answer is "adjacent, supplementary".
