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GaryK [48]
2 years ago
6

Hey can you somebody help me with this problem

Mathematics
1 answer:
irina [24]2 years ago
4 0

Step-by-step explanation:

sinx=20/36

x=sin-¹20/36

x=34

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4/r+8/f=5/g solve for f
Olegator [25]

Answer:

Let's solve for f.

4

r

+

8

f

=

5

g

Step 1: Multiply both sides by fr.

4f+8r=

5fr

g

Step 2: Multiply both sides by g.

4fg+8gr=5fr

Step 3: Add -5fr to both sides.

4fg+8gr+−5fr=5fr+−5fr

4fg−5fr+8gr=0

Step 4: Add -8gr to both sides.

4fg−5fr+8gr+−8gr=0+−8gr

4fg−5fr=−8gr

Step 5: Factor out variable f.

f(4g−5r)=−8gr

Step 6: Divide both sides by 4g-5r.

f(4g−5r)

4g−5r

=

−8gr

4g−5r

f=

−8gr

4g−5r

Answer:

f=−8gr4g−5r

7 0
3 years ago
Read 2 more answers
PLEASE HELP FAST GEOMERTY
Paladinen [302]

Answer:

26

Step-by-step explanation:

125+29=154

180-154=26

7 0
3 years ago
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Granola costs $6.50 per pound. Assorted nuts cost $9 per pound. How many pounds of granola and nuts are needed to make 9 pounds
bezimeni [28]

Answer:

  • 3.6 pounds of granola and 5.4 pounds of nuts

Step-by-step explanation:

Let the required granola be x pounds, then amount of nuts is 9 - x.

<u>The price of the mixture is as below equation:</u>

  • 6.5x + 9(9 - x) = 8*9
  • 6.5x + 81 - 9x = 72
  • 81 - 2.5x = 72
  • 2.5x = 81 - 72
  • 2.5x = 9
  • x = 9/2.5
  • x = 3.6

<u>Find the amount of nuts:</u>

  • 9 - 3.6 = 5.4
7 0
2 years ago
One number is seven more than a second number. Twice the first is 2 less than 3 times the second. Find the numbers.
Keith_Richards [23]

Step-by-step explanation:

Linear equations. Make 2 new equations from the question. Name the first number as x and the second as y...

4 0
3 years ago
Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the
motikmotik

<u>Given</u>:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

<u>Coordinates of the point A':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point A(-2,3), we get;

(-2,3)\rightarrow (-2,-3)

Thus, the coordinates of the point A' is (-2,-3)

<u>Coordinates of the point B':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point B(0,3), we get;

(0,3)\rightarrow (0,-3)

Thus, the coordinates of the point B' is (0,-3)

<u>Coordinates of the point C':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point C(-1,-1), we get;

(-1,-1)\rightarrow (-1,1)

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

8 0
3 years ago
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