3,001...............................................
4.
h(f(x)=h(2x-1)=
(2x-1)^2+1=
4x²-4x+1+1=
4x²-4x+2
5.
f(f(x))=2(2x-1)-1=4x-2-1=4x-3
6.
f o g (x)=f(g(x))
h o g (x)=h(g(x))=
(3x)^2+1=
9x²+1
Answer:
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Step-by-step explanation:
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The miners elevator is deeper than that of the equipment.
<h3>How to calculate the speed of elevator?</h3>
Speed of the equipment elevator is been given as 4 feet per second and Speed of the miners elevator = 15 feet per second.
Time of descent of the equipment elevator = (30 + 14) = 44 seconds
Then, distance can be calculated as (speed x time) which equals to = 4 x 44 = - 176 ft
but distance of the miners elevator after 14 seconds is:
speed = (15 x 17) = 225
therefore, distance = - 225 feet
Thus after another 14 seconds, the equipment elevator is at a depth of 176 feet (-176 feet), while the miners elevator is at a depth of 225 feet (-225 feet) below the surface.
Learn more elevator at:
brainly.com/question/13342159
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Assuming that you mean that the equation of line c is
![y=-\dfrac{4}{3}x-4](https://tex.z-dn.net/?f=y%3D-%5Cdfrac%7B4%7D%7B3%7Dx-4)
We can deduce that the slope of line c is
![m_c=-\dfrac{4}{3}](https://tex.z-dn.net/?f=m_c%3D-%5Cdfrac%7B4%7D%7B3%7D)
since the slope is the coefficient multiplying x in the equation of a line. Since we want line d to be perpendicular to line c, their slope must be in the following relationship:
![m_cm_d=-1 \iff m_d=-\dfrac{1}{m_c}=-\dfrac{1}{-\frac{4}{3}}=\dfrac{3}{4}](https://tex.z-dn.net/?f=m_cm_d%3D-1%20%5Ciff%20m_d%3D-%5Cdfrac%7B1%7D%7Bm_c%7D%3D-%5Cdfrac%7B1%7D%7B-%5Cfrac%7B4%7D%7B3%7D%7D%3D%5Cdfrac%7B3%7D%7B4%7D)
So, line d has slope 3/4 and passes through point (4,-4). Use the equation
![y-y_0=m_d(x-x_0)](https://tex.z-dn.net/?f=y-y_0%3Dm_d%28x-x_0%29)
to find the equation of line d, where
![x_0=4,\quad y_0=-4,\quad m_d=\dfrac{3}{4}](https://tex.z-dn.net/?f=x_0%3D4%2C%5Cquad%20y_0%3D-4%2C%5Cquad%20m_d%3D%5Cdfrac%7B3%7D%7B4%7D)