Line CB touches circle A only at one point (point B), hence CB is a tangent.
<h3>What is a
circle?</h3>
A circle is the locus of a point such that its distance from a fixed point (center) is always constant.
When a line intersects a circle in exactly one point the line is said to be tangent to the circle
Hence since Line CB touches circle A only at one point (point B), hence CB is a tangent.
Find out more on circle at: brainly.com/question/24375372
The difference of the expression is as follows:
(6y⁴ + 3y² - 7) - (12y⁴ - y² + 5) = - 6y⁴ + 4y² - 12
3(x - 5) - (2x + 4) = x - 19
<h3>How to find the difference of the expression?</h3>
The difference of the expression can be found when we combine the like terms.
Therefore,
(6y⁴ + 3y² - 7) - (12y⁴ - y² + 5)
6y⁴ + 3y² - 7 - 12y⁴ + y² - 5
6y⁴ - 12y⁴ + 3y² + y² - 7 - 5
- 6y⁴ + 4y² - 12
3(x - 5) - (2x + 4)
3x - 15 - 2x - 4
3x - 2x - 15 - 4
x - 19
learn more on expression here: brainly.com/question/14294918
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Answer:
y²=4√2.x
Step-by-step explanation:
The focus is at (0,4) and directrix is y=x or x-y =0, for a parabola P.
The distance between the focus and the directrix of the parabola P is
=
{Since the perpendicular distance of a point (x1, y1) from the straight line ax+by+c =0 is given by 
}
Let us assume that the equation of the parabola which is congruent with parabola P is y²=4ax
{Since the parabola has vertical directrix}
Hence, the distance between focus and the directrix is 2a = , {Two parabolas are congruent when the distances between their focus and the directrix are same}
⇒ a=√2
Therefore, the equation of the parabola is y²=4√2.x (Answer)
Answer:
It would be D because you are timing 2 by a number which would have n together
Hope this helped
