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adoni [48]
2 years ago
14

Describe a sequence of transformations that can be performed to polygon ABCDE to prove that it is similar to polygon FGHIJ

Mathematics
1 answer:
maxonik [38]2 years ago
8 0

Answer:

answer below

Step-by-step explanation:

ABCDE go through dilation over center (6 , -2) with factor of 1/2 to FGHIJ

AB // FG slope: -2 , √20:√5 = 2: 1

BC // GH // X axis 8:4 = 2:1

CD // HI, slope= 1 , √8:√2 = 2:1

DE // IJ // x axis, 4:2 = 2:1

EA // JF // y axis, 2:1

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The last one is correct!
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3 years ago
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Train travels at 3 hours if it's speed is 65 miles per hour. It takes the train 2.5 hours if it's speed is 78 per hour . Identif
seraphim [82]

Step-by-step explanation:

Let the original speed of the train be x km/h.

Time taken to cover a distance of 360 km =  360/x hours.

New speed of the train = (x+5) km/h.

Time taken to cover a distance of 360 km at new speed = 360/x+5 hours.

Since, the train takes 1 hour less time,

∴360/x - 360/ x+5 = 1

⇒360 (5) = x² + 5x

⇒1800 = x² + 5x

⇒x² + 5x - 1800 = 0

⇒x² + 45x - 40x - 1800 = 0

⇒x (x+45) - 40( x +45) = 0

⇒(x+45) (x-40) = 0

⇒x = (-45), 40

But since speed cannot be in negative.

∴x = 40 km/hr.

Hence, the original speed of the train is 40 km/h.

3 0
3 years ago
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Point B is halfway between A and C. The distance from C to D is the same as the distance from D to E, which is the same as the d
jek_recluse [69]

Answer:

60

Step-by-step explanation:

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BC = AC/2

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so (1/2) (BC) (CE) = (1/2) (AC/2) (2/3)CF = (1/2)(2/3)(180) = 60 sq cm

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3 years ago
Plot the points : A(4,5), B(3,3), C(6,9), D(8,13), E(10,15) all but one of the points are on the same line which is not?
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Answer:

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3 0
2 years ago
The rate of change in sales S is inversely proportional to time t (t > 1), measured in weeks. Find S as a function of t when
Zanzabum

Answer:

<h2>S = 250/t</h2>

Step-by-step explanation:

If the rate of change of sales is inversely proportional to the time t, this is expressed mathematically as ΔS ∝ 1/Δt

ΔS = k/Δt where k is the constant of proportionality

If ΔS = S₂-S₁ and Δt = t₂-t₁

S₂-S₁ = k/ t₂-t₁

If the sales after 2 and 4 weeks are 162 units and 287 units respectively, then when S₁  = 162, t₁ = 2 and when   S₂ = 287, t₂ = 4.

On substituting this values into the given functions, we will have;

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cross multiplying

k = 125* 2

k = 250

Substituting k = 250 into the function ΔS = k/Δt

ΔS = 250/Δt

S = 250/t

<em>Hence the value of S as function of t when the sales after 2 and 4 weeks are 162 units and 287 units, respectively is expressed as S = 250/t</em>

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3 years ago
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