Answers: b, d and e
b.The graph has a relative minimum
d. The graph has an x intercept at 3,0
e. the graph has an y intercept at 0,-15
f(x)=(x+5)(x-3)
The given equation is in the form of f(x) = a(x-b)(x-c)
If 'a' is positive then graph has a relative minimum
If 'a' is negative then graph has a relative maximum
Here a=1 that is positive so graph has a relative minimum .
To find x intercept we set f(x) =0 and solve for x
0=(x+5)(x-3)
x+5 =0 -> x = -5 so x intercept is (-5,0)
x - 3=0 -> x= 3 so x intercept is (3,0)
To find y intercept we plug in 0 for x
y=(x+5)(x-3)
y=(0+5)(0-3) = -15
so y intercept is (0,-15)
Y=3
Simplify
Distribute
Combine like terms
Add 2y to both sides
Add 2 to both sides
Divide by 3 , both sides.
If u want me to write the numbers and all just reply
2 less than (3 times a number) is the same as (the number plus 10)
2 less than (3*x) = (x + 10)
3x - 2 = x + 10
From here, you solve! :)
3x - 2 - x = x + 10 - x
2x - 2 = 10
2x - 2 + 2 = 10 + 2
2x = 12
2x / 2 = 12 / 2
x = 6
Hope this helps! :)
Answer:
Step-by-step explanation:
T(1)=1=0*x^3 0*x^2 0*x 1*1 T(x)=x-1=0*x^3 0*x^2 1*x (-1)*1 T(x^2)=2x^2-6x 6=0*x^3 2*x^2 (-6)*x 6 T(x^3)=6x^3-48*x^2 141*x-141 T(x^4)=24*x^3-204*x^2 628*x-604*1 collect the coefficient matrix and take its transpose
0 0 0 6 24
0 0 2 -48 -204
0 1 -6 141 628
1 -1 6 -141 -604
Answer:
12
Step-by-step explanation:
u have to mutypl and div it up sum and k/=+56+8=90/h=+5689-097/p=11+y=1+11=12