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mezya [45]
3 years ago
9

1. –2v – 7 = –23 (1 point) 15 8 –8 –15 2. Start Fraction x over 4 End Fraction – 5 = –8 (1 point) –27 –12 –7 12

Mathematics
1 answer:
lara [203]3 years ago
4 0

Answer:

  1. v = 8
  2. x = -12

Step-by-step explanation:

1. I like to work with positive numbers, so the first thing I'd do is multiply the equation by -1.

  2v + 7 = 23

  2v = 16 . . . . . subtract 7

  v = 8 . . . . . . . divide by 2

<em>Check</em>

  -2(8) -7 = -23 . . . . true

___

2. (x/4) -5 = -8

  x/4 = -3 . . . . . . . add 5

  x = -12 . . . . . . . . multiply by 4

<em>Check</em>

  (-12/4) -5 = -8 . . . . true

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If the errors produced by a forecasting method for 3 observations are +3, +3, and −3, then what is the mean squared error?
KiRa [710]

Answer:

9

Step-by-step explanation:

The mean squared error (MSE)of a set of observations can be calculated using the formula :

(1/n)Σ(Actual values - predicted values)^2

Where n = number of observations

Steps :

Error values of each observation (difference between actual and predicted values) is squared.

Step 2:

The squared values are summed

Step 3:

The summation is the divided by the number of observations

The difference between the actual and predicted values is known as the ERROR.

(1/n)Σ(ERROR)^2

n = 3

Error = +3, +3, - 3

MSE = (1/3)Σ[(3)^2 + (3)^2 + (-3)^2]

MSE = (1/3) × [9 + 9 + 9]

MSE = (1/3) × 27

MSE = 9

5 0
3 years ago
Can you please give me 5 excersices to get perimeter and area, square or rectangle
igor_vitrenko [27]
◼️ This is a square. Each side is 5cm. What is the area and perimeter????




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8 0
3 years ago
Read 2 more answers
At the start of the month, the value of an investment was $48.45. By the end of the month, the value of the investment changed b
Klio2033 [76]
$34.65 because of 48.45-13.80
4 0
3 years ago
B(n)=4-6(n-1) find the fourth term
kompoz [17]

Answer:

b(4) = -14

Step-by-step explanation:

b(n)=4-6(n-1)

let n=4

b(4) = 4 - 6(4-1)

b(4) = 4-6*3

b(4) = 4-18

b(4) = -14

6 0
4 years ago
Which of these strategies would eliminate a variable in the system of equations?
mariarad [96]

Answer:

<em>Multiply the bottom equation by -3/2 then add the equations. </em>

<em>Multiply the top equation by-3. then add the equations </em>

<em> </em>

Step-by-step explanation:

Given the simultaneous equation

2x- 6y=6  ... 1

6x - 4y = 2 ... 2

To eliminate a variable, we have to make the coefficient of one of the variable to be the same.

Multiply equastion 1 by -3

-6x+18y= -18  

6x - 4y = 2

Add the result:

-6x + 6x + 18y-4y = -18+2

18y-4y = -18+2

14y = -18

y = -9/7

Another way is to Multiply the bottom equation by -3/2 then add the equations.

Multiplying equation 2 by -3/2 will give;

6x(-3/2) - 4y(-3/2) = 2(-3/2)

-9x + 6y = -3

Add to equation 1;

2x- 6y=6

-9x + 2x + 0 = -3+6

-7x = 3

x = -3/7

Hence the correct two options are;

<em>Multiply the bottom equation by -3/2 then add the equations. </em>

<em>Multiply the top equation by-3. then add the equations </em>

<em> </em>

<em></em>

<em></em>

4 0
3 years ago
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