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alex41 [277]
2 years ago
13

A circle is centered at (-4, 6) and has a radius of 9. What is the equation of the circle? Question 3 options: (x+4)2+(y−6)2=18

(x+4)2+(y−6)2=81 (x−4)2+(y+6)2=18 (x−4)2+(y+6)2=81
Mathematics
1 answer:
Lera25 [3.4K]2 years ago
3 0

Answer:

(x+4)² + (y-6)² = 81

Step-by-step explanation:

<u>General equation of a circle :</u> (x-h)² + (y-k)² = r²

where (h,k) is at center and r = radius

Here we are given that the circle has a center at (-4,6) and a radius of 9

So we have (h,k) = (-4,6) so h = -4 and k = 6 and radius = 9 so r = 9

<u>Plugging in values into general equation</u>

Recall that the general equation of a circle is (x-h)² + (y-k)² = r²

we have h = -4 , k = 6 and r = 9

==> plug in values

doing so we acquire (x-(-4))² + (y-6)² = 9²

==> apply double negative sign rule

(x+4)² + (y-6)² = 9²

==> evaluate exponent

(x+4)² + (y-6)² = 81

And we are done!

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Mashcka [7]

Answer:

Please check the explanation.

Step-by-step explanation:

  • As we know that the values in the table represent a function​ only if there there is only 1 input for every output.

Given the table 1

x              y

-12           2

-10           10

0              -2

5              -6

8               -11

15              -15

From the table, it is clear that for each input there exists a unique output.

i.e.

According to the given table,

y = 2 at x=-12

y = 10 at x=-1 0

y = -1 at x=0

y = -11 at x=8

y = -15 at x=15

From the table, it is clear that for each input x, it has a unique output y.

Hence, table 1 is a function.

Given the table 2

x              y

9            -18

-20           0

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9                17

11              19

This table does not produce a function, because the input x=9 produces two outputs.

i.e.

at x = 9, the y = -18

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3 0
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kenny6666 [7]

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Shift the graph of the function y = x², 5 units down /look at the picture #1/.

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