Y = -1 is a horizontal line going through "-1" on the y axis
Note that the point (1,2) is exactly 3 units of distance above the line y = -1
When we reflect across this line, the point (1,2) will just move straight down to exactly 3 units of space below the line y = -1. Since we are not shifting left or right, the x coordinate of our original point will not change. The y coordinate of our original point will now need to be reduced by 6(3 units down to get to the line of reflection and then 3 more down to get to the image location)
The coordinates of the image point will be (1, -4)
Now we need to do the same process with (1, -4) being reflected across y=1
Note (1,-4) is 5 units of distance below the line y = 1 , so we need to reflect the point upward so that the image point is located exactly 5 units of distance above the line y = 1 Again, the x coordinate does not change, and our final image coordinates are (1, 6)
I guess more simply stated, if you're just looking for the number in the green box it would be " 1 " .. Reflecting points across horizontal lines only result in changes of the "y" coordinate since there is no shift left or right.
It’s 4.08x10 to the 6 power. Which is answer A
Answer:
1.No, 143 is not a prime number. The list of all positive divisors the list of all integers that divide 143 is as follows: 1, 11, 13, 143. To be 143 a prime number, it would have been required that 143 has only two divisors, itself and 1.
2.Since the polynomial can be factored, it is not prime.
Answer: The 2 answers are inequality form and interval notation: n>200, and (200, ∞).
Step-by-step explanation: To solve for n, you’ll need to simplify the both sides of the inequality, and then isolating the variable.
Answer: y = 3x-1
Step-by-step explanation: I was never the best at doing this, but here it goes...
first start with the formula Y2-Y1/X2-X1 for this problem, lets say your Y2 is -1, your Y1 is 5, your X2 is 0, and your X1 is 2, making your equation -1-5/0-2 which equals -6/-2, which can be qritten as 3. this is your slope.
now take the equation Y-Y1 = M (X-X1) m is your slope, which is 3 in this case as stated above. your X1 is2, your Y1 is 5. plug this in and you get
y-5 = 3 (x-2) which you put into slope intercept form, which is y = mx + b
your answer should be y = 3x-1
