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3 years ago

What value is equivalent to (3^6)^3?

Mathematics

2 answers:

Anika [276]3 years ago

4 0

Answer:

1/2 is the simplified fraction for 3/6.

Step-by-step explanation:

im not sure but i think thats it

snow_lady [41]3 years ago

4 0

Answer:

387,420,489

Step-by-step explanation:

First, evaluate what is in the parentheses. This is equivalent to 729. Now take this number, and cube it (or do 729^3). This is equivalent to 387420489.

The ^ symbol means 'to the power of'.

For example, if you want to raise the number 5 to the power of 4, then you would do 5 ^ (to the power of) 4. Also looks like this: $5^{4}$

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Vlada [557]

The measure of angle 4 would be the same as its opposite exterior angle which is given. It will have a measurement of 38 degrees. These angles are called alternate exterior angles. Hope this answers the question. Have a nice day. Feel free to ask more questions.

6 0

3 years ago

Help!! I really don't get it and if you can please give explanation

Mice21 [21]

Answer: 1/20

Step-by-step explanation: = 1+8:36= 9 hours and 36 minutes

= 9+ 36/60= 9 3/5 hours

=48/5

Decrease per hour= 12/25 divided by 48/5

= 12/25 times 5/48= 1/20

Ans 1/20

6 0

3 years ago

What is 1 3/4 as a percent

KiRa [710]

Answer:

267% and 400%

6 0

3 years ago

Read 2 more answers

Someone please help! (listing BRAINLIST and giving points) :D

LekaFEV [45]

Answer:

opp/adj

havent u pay attention in ur math class?

you will have to find the opp using a^2+b^2+c^2

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t

natta225 [31]

The area of the surface given by $\vec r_1(u,v)$ is 1. In terms of a surface integral, we have

$1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

By multiplying each component in $\vec r_1$ by 5, we have

$\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}$

and the same goes for the derivative with respect to $v$ . Then the area of the surface given by $\vec r_2(u,v)$ is

$\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}$

8 0

3 years ago