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jarptica [38.1K]
3 years ago
15

What value is equivalent to (3^6)^3?

Mathematics
2 answers:
Anika [276]3 years ago
4 0

Answer:

1/2 is the simplified fraction for 3/6.

Step-by-step explanation:

im not sure but i think thats it

snow_lady [41]3 years ago
4 0

Answer:

387,420,489

Step-by-step explanation:

First, evaluate what is in the parentheses. This is equivalent to 729. Now take this number, and cube it (or do 729^3). This is equivalent to 387420489.

The ^ symbol means 'to the power of'.

For example, if you want to raise the number 5 to the power of 4, then you would do 5 ^ (to the power of) 4. Also looks like this:  5^{4}

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motikmotik

Answer:

900 j

Step-by-step explanation:

KE=1/2mv^2

so:

1/2x(2kg)x(30m/s)^2

is 900 joules. :)

6 0
3 years ago
Which expression is equivalent to 3/4(x-5y)<br><br>please help!!! ​
irakobra [83]

Step-by-step explanation:

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8 0
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Find the area of the triangle below.
xenn [34]

Answer:

Well t find the area of a triangle, you need to multiple Base x height. That gives you 43.56. Now you divide by 2. So the end product will give you 21.78. Those same rules apply to every time you are finding the area of a triangle.

Step-by-step explanation:

7 0
2 years ago
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ONLY ANSWER THIS IF YOU HAVE AN EXPLANATION AND IF YOU KNOW WHAT THE ANSWER IS.
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6 0
3 years ago
A dog chases a squirrel. The dog is originally 200 feet away from the squirrel. The dog's speed is 150 feet per minute. The squi
Dafna11 [192]

Answer:

15 seconds

Step-by-step explanation:

If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy:  the dog's rate is 150 and the squirrel's is 100.  The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know:  the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up.  Since we don't know what d is, we will just call it d!  Now it seems as though we have 2 unknowns which is a problem.  However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other.  Here's the dog's equation:

d = rt

d+200 = 150t

And the squirrel's:

d = 100t

If we solve both for t and set them equal to each other we have:

\frac{150}{d+200} =\frac{100}{d}

Now we can cross multiply to solve for d:

150d = 100d + 20,000 and

50d = 20,000

d = 400

But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took.  So sub that d value back into one of the equations we have solved for t and do the math:

t=\frac{100}{d}=\frac{100}{400} =\frac{1}{4}

That's 1/4 of a minute which is 15 seconds.

6 0
3 years ago
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