$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-3}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[5-(-3)]^2+[-6-2]^2}\implies d=\sqrt{(5+3)^2+(-8)^2} \\\\\\ d=\sqrt{8^2+8^2}\implies d=\sqrt{2(8^2)}\implies d=8\sqrt{2}$

8 0

4 years ago

Please help finding the volume of the cylinder. Extra points and brainiest will be given.

nadya68 [22]

Answer: 141.3/3=47.1 so then 47.1x3.14=147.89400

Step-by-step explanation:

7 0

3 years ago

The weight of laboratory mice follows a normal distribution, with a mean of 0.68 ounce and a standard deviation of 0.02 ounce. W

elena-14-01-66 [18.8K]

Answer:

A.99.7%

Step-by-step explanation:

We are given;

Mean of a distribution, μ as 0.68 ounce
Standard deviation, σ as 0.02 ounce
The range values of X between 0.62 ounce and 0.74 ounce

We are required to calculate the percentage of the weight to be between 0.62 ounce and 0.74 ounce

Step 1: Calculate the Z-score

To get the Z-score we use the formula;

Z-score = (x-μ)/σ

Therefore, when x = 0.62

Then z score = (0.62 - 0.68 ) ÷ 0.02

= -3

When, x = 0.74

Then, Z score = (0.74 - 0.68) ÷ 0.02

= 3

Step 2: we use the Z-score table or the empirical rule

Using the Z-score table;

P(-3 < z < 3) = 99.7%.

Therefore; the percentage of mice that weigh between 0.62 ounce and 0.74 ounce is 99.7%.

7 0

3 years ago

Jin sells concert tickets at the theater box office. The ratio of student tickets to adult tickets sold is 4 : 5. Each student t

Zina [86]

Answer:

84 tickets

Step-by-step explanation:

[189÷(4+5)]×4

=189÷9

=21×4

= 84 tickets

8 0

3 years ago

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