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oee [108]
2 years ago
11

Would very much appreciate it if you guys helped out

Mathematics
1 answer:
denis-greek [22]2 years ago
4 0
Answer: x^2 + 6x – 7 = 0


The solutions x = -7 and x = 1 can be written as:

(x+7)(x-1) = 0

(Because you find the solution values for x from the brackets e.g (x+7) to get x=-7, dunno how to explain it better sry)

From which you can expand the brackets and find the answer in quadratic form.

(x+7)(x-1) = 0

Expand the brackets

x^2 + 7x – x – 7 = 0

x^2 + 6x – 7 = 0
You might be interested in
How do I solve this question?
Tanya [424]
Before attempting to solve this question, we must first know three things.

1. A straight line has a measure of 180 degrees.

2. When two angles add up to 180 degrees, those angles are called supplementary.

3. The interior angles of a triangle add up to 180 degrees.

We can see ∠ECT = 180 degrees.

∠DCT is supplementary to ∠DCE.

∠DCT = 140 degreees
∠DCE = x degrees

x + 140 = 180

Solve for x.

x + 140 = 180
x = 40 <-- Subtract 140 from each side

∠DCE = 40 degrees

We know the two interior angles of ΔDEC.

45 + 40 + x = 180

Solve for x.

45 + 40 + x = 180
85 + x = 180 <-- Combine like terms
x = 95

So, the missing angle is equal to 95 degrees.
6 0
3 years ago
Is -10r to the third power plus 3r minus 18 a polynomial?l
Andreyy89
No! it’s a trinomial, a polynomial consists of 4 or more terms :)
4 0
3 years ago
40 is 50% of what number
dimulka [17.4K]
40 is 50% of 80.

80 ÷ 2 = 40
5 0
3 years ago
Read 2 more answers
In a school, for every 5 boys there are12 girls. if there are 300 gilrs how many boys are there?
andrezito [222]
The answer is 125 boys 125:300
4 0
4 years ago
Read 2 more answers
Jennifer starts with a population of 100 amoebas that doubles in size every minute for a number of minutes, m. She writes the ex
Zina [86]

Answer:

100(2m)

(1+0.4)

Nathan=0.4 is the percent added =the 40 percent added to the 10 amoebas

Jennifer=the first equation is how many total amoebas Jennifer has in total

<h3><u>Hope this helps!</u></h3>
7 0
3 years ago
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