Answer:
Let's choose the three odd consecutive numbers 1, 3, and 5.
3^2=9
1•5=5
9-5=4
Let's try the same thing, but with the numbers 101, 103, and 105.
103^2=10609
101•105=10605
10609-10605=4
So, yes, the square of the second number out of three consecutive odd numbers is four greater than the product of the first and the third numbers.
Https://www.khanacademy.org/.../limits...limits.../one-sided-limits-fr...<span>
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We know that
In any quadrilateral where the vertices are on the circumference of a circle, the opposite angles add up to

degrees.
So,
in this problem

therefore
the answer is
Answer:
Step-by-step explanation:
Hello, I assume that you mean

The product is -36.

So in this example, it means that the sum is 5 and the product is -36.
Thank you
But what say it again wit what is this