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vova2212 [387]
3 years ago
8

Can someone help me ASAP!!!

Mathematics
1 answer:
Nostrana [21]3 years ago
8 0

9514 1404 393

Answer:

  f(x) = {-x for x < 2; 2x-3 for x ≥ 2}

Step-by-step explanation:

The blue line extending to the left has a slope of -1 and a y-intercept of 0. Its equation is y = -x. That part of the definition of f(x) is applicable for values of x less than 2. (The open dot at (2, -2) tells you that point is not included.)

The red line extending to the right has a slope = rise/run = 2/1 = 2. The y-intercept can be found by extending the line to the y-axis, or from the computation ...

  b = y -mx

  b = 1 -2(2) = -3 . . . . . for the point (x, y) = (2, 1)

Then the slope-intercept equation for the red line is ...

  y = 2x -3

That part of the definition of f(x) is applicable for values of x ≥ 2. The solid dot tells you the point (2, 1) is included.

Putting these parts together, we get ...

  f(x)=\left\{\begin{array}{cc}-x&\text{if $x

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Viktor earns $15.75 per hour cleaning pools. How much money will Viktor earn if he cleans 22 pools? Round your answer to the nea
Bingel [31]
$347

15.75×22=346.5=347
4 0
3 years ago
Just determine whether its positive or negative please
NeX [460]
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3 0
2 years ago
Suppose m = 2 + 6i, and | m + n | = 3√10, where n is a complex number.
Ksju [112]

Answer: a) √50

b) n = 1 + 7i

Step-by-step explanation:

first, the modulus of a complex number z = a + bi is

IzI = √(a^2 + b^2)  

The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:

m = 2 + 6i

n = a  + bi

Im + nI = 3√10

Im + n I = √(a^2 + b^2 + 2^2 + 6^2)= 3√10

            = √(a^2 + b^2 + 40) = 3√10

             a^2 + b^2 + 40 = 3^2*10 = 9*10 = 90

             a^2 + b^2 = 90 - 40 = 50

            √(a^2 + b^2 ) = InI = √50

The modulus of n must be equal to the square root of 50.

now we can find any values a and b such a^2 + b^2 = 50.

for example, a = 1 and b = 7

1^2 + 7^2 = 1 + 49  = 50

Then a possible value for n is:

n = 1 + 7i

6 0
3 years ago
A cone has a volume of about 235.5 cubic centimeters. If the height is 9 centimeters what is the radius of the cone?
sp2606 [1]
Volume of a cone = 1/3 π r² h 

235.5 = 1/3 (3.14) r² (9) 

(3.14) r² (9)  = 706.5

r² = 25

r = 5

Answer: Radius = 5 cm
8 0
3 years ago
Read 2 more answers
I need help with this
Triss [41]
Since 12 is hypotenuse, formula we would use is:
12^2=5^2+x^2
144=25+x^2
x^2= 144-25
x^2=119
x= √119
x=10.9087
Rounded to nearest tenth,
x=10.9
Good luck.
4 0
3 years ago
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