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2 years ago

10

Heyyyyyyyyyyyyyyyyyyyyyyyyyyyy

2 answers:

jonny [76]2 years ago

4 0

1. 17.5

2. B = 3 A=3 area = 22

3. =18

4. =29

nadezda [96]2 years ago

3 0

1. triangle + rectangular = (1/2 x 6 x 4) + (6 x 7.5) = 57 ft^2

2. A + B + C = (1/2 x 2 x 3) + (11 x 4) + (1/2 x 3 x 3) = 51,5 ft^2

3. square + rectangular = (2 x 2) + (3 x 6)= 22 m^2

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Which function in Excel is used to perform a test of independence? a. T.TEST b. CHISQ.TEST c. NORM.S.DIST d. Z.TEST

denis23 [38]

Answer:

b. CHISQ.TEST

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

The statistic is given by:

$\chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}$

In order to calculate the p value we need to have in count the degrees of freedom , on this case $df=(rows-1)(#cols-1)$ . And we can calculate the p value would be given by:

$p_v =P(\chi^2 >\chi^2_{calc})$

But the correct comand is given by:

b. CHISQ.TEST(Actual range, Expected range)

We just need to put in one column the Observed values and in other the expectec values.

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3 years ago

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KonstantinChe [14]

Answer:

D. LN = KM is not correct

Step-by-step explanation:

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2 years ago

Write an equation for the nth term of the geometric sequence 3584, 896, 224... Find the sixth term of this sequence

lions [1.4K]

Answer:

Step-by-step explanation:

r = $\frac{a_n}{a_{n-1}} = \frac{896}{3584} = \frac{1}{4}$

Using the geometric series formula for the <em>n</em>th term:

$S_n = a \cdot \frac{1-r^n}{1-r} => S_{6} = 3584 \cdot \frac{1 - (\frac{1}{4})^{6} }{1 - \frac{1}{4} } = 4777\frac{1}{2}$

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3 years ago

use the guide to construct a two column proof proving △aec≅△deb, given that ca is parallel to db and e is the midpoint of ad. gi

MrMuchimi

By using the AAA congruence property of Triangles, △aec≅△deb is proved

It is given two triangles, Δaec and Δdeb, where e is the common point known as the midpoint of ad

Also, it is given that,

ca ║db

We need to prove that, △aec≅△deb

Then we'll use AAA congruence property of Triangles to prove the situation

As ca ║db

then, ∠cae = ∠ebd (Alternate angles)

∠ace = ∠edb (Alternate angles)

and ∠aec = ∠deb (common angles)

Thus, by AAA congruence property, △aec≅△deb

Hence, proved

To learn more about, congruence property, here

brainly.com/question/2039214

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Vladimir [108]

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2 years ago

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