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lara31 [8.8K]
3 years ago
8

Pinky Bauer, Chief Financial Officer of Harrison Haulers, Inc., suspects irregularities in the payroll system. She knows that 2,

500 payroll vouchers have been issued since January 1, 2000, and her staff doesn't have time to inspect each voucher. So, she orders her staff to inspect the last 200 vouchers. Her sample is a ___________.
A. stratified sample
B. simple random sample
C. convenience sample
D. systematic sample
Mathematics
1 answer:
kherson [118]3 years ago
5 0

Answer:

The correct option is (C) convenience sample.

Step-by-step explanation:

Convenience sampling is a kind of non-probability sampling, i.e. all items does not have an equivalent chance or probability of being selected. This type of sampling method does not comprises of random collection of items.

Convenience sampling is where we take in items which are easy to reach or collect.

For example, sampling the the students of your own class or collecting sample from your own neighborhood.

In this case the Chief Financial Officer of Harrison Haulers, Inc. asks her staff to inspect the last 200 vouchers of the 2500 payroll vouchers that have been issued since January 1, 2000.

She did so because her staff did not have that much time in hand and it is quite convenient to check the last 200 vouchers.

This is because it is quite easy to review the last 200 payroll vouchers since they would be the most recent ones and quite easily accessible.

So, the sampling method used by the Chief Financial Officer of Harrison Haulers, Inc. is Convenience sampling.

Thus, the correct option is (C).

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The midpoint of segment AB is (-7, 10) and endpoint A is located at (3, -1). Find the other endpoint B. Show all work.
dusya [7]

Answer:

B(-17,21)

Step-by-step explanation:

The midpoint of two points is the average of the x coordinates and the average of the y coordinates.

Given

A(3, -1)

and we let the other end point B be B(x,y)

and midpoint is (-7,10)

So, the average of 3 and x is -7, and

the average of -1 and y is 10

We can solve for x first:

\frac{3+x}{2}=-7\\3+x=2*-7\\3+x=-14\\x=-14-3\\x=-17

and now solving for y:

\frac{-1+y}{2}=10\\-1+y=2*10\\-1+y=20\\y=20+1\\y=21

So, the other point B is:

B(-17,21)

6 0
3 years ago
Find the midpoint of AB for: A(7,0)|and B(0,3)​
liberstina [14]

Answer:

\boxed {\boxed {\sf (\frac {7}{2}, \frac{3}{2}) \ or \ (3,5, 1.5) }}

Step-by-step explanation:

The midpoint is essentially a point with the average of the 2 x-coordinates and the 2 y-coordinates.

The formula is:

(\frac {x_1+x_2}{2}, \frac{y_1+y_2}{2})

We are given two points: A (7,0) and B (0, 3). Remember points are written as (x, y).

Therefore,

x_1= 7 \\y_1=0 \\x_2=0 \\x_2=3

Substitute the values into the formula.

(\frac {7+0}{2}, \frac{0+3}{2})

Solve the numerators first.

(\frac {7}{2}, \frac{3}{2})

The midpoint can be left like this because the fractions are reduced, but it can be written as decimals too.

(3.5, 1.5)

3 0
3 years ago
Grandma has 14 red roses and 7 pink roses how many more red roses than pink does she have explain how you solve the promblem
Helga [31]
She has 7 more roses. you can subtract to find the difference. 14-7=7
4 0
3 years ago
Simpliest radical form for the square root of 72​
DIA [1.3K]

Answer:

√72=2⋅3√2.

Step-by-step explanation:

This is your answer I am pretty sure this is correct.

If not please let me know.

6 0
2 years ago
Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2
Agata [3.3K]
\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
-------------------------------

\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
\qquad \qquad 42\\
||v1||=\sqrt{(-6)^2+4^2}\\
\qquad \sqrt{52}\\
||v2||=\sqrt{(-3)^2+6^2}\\
\qquad \sqrt{45}
\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
\measuredangle \theta =cos^{-1}\left(  \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o
8 0
3 years ago
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