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2 years ago

8 and 1/4 + 3 and 5/6

Mathematics

1 answer:

k0ka [10]2 years ago

8 0

Answer:

12 1/12

Step-by-step explanation: so, we have to make the bottom number the same as eachother or we will not be able to add effectively. So the first number that both 4 and 6 go into is 12, as you can see if we count by the numbers to get to the answer

4,8,12

6,12

So, now that we have that part figured out we would then have to multiply the top the same amount as we multiplied the bottom. So 1/4x3 and 5/6x2

So we would multiply both the top and the bottom the same amount.

1/4x3=3/12

5/6x2=10/12

So now that we have that figured out everything else is pretty straight forward.

We would add the whole numbers with eachother and the fractions with eachother.

8+3=11

3/12+10/12=13/12

so we can see that it would equal, 11 and 13/12 or 12 and 1/12

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5x + 5 – 3x = 14 – 2x + 7 + 8x

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5x-3x+2x-8x=-5+14+7
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3 years ago

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Two students from a group of eight boys and 12 girls are sent to represent the school in a parade.If the students are chosen at

jolli1 [7]

Answer:

The probability that the students chosen are not both girls is 62/95 ⇒ (c)

Step-by-step explanation:

* Lets explain how to find the probability of an event

- The probability of an Event = Number of favorable outcomes ÷ Total

number of possible outcomes

- P(A) = n(E) ÷ n(S) , where

# P(A) means finding the probability of an event A

# n(E) means the number of favorable outcomes of an event

# n(S) means set of all possible outcomes of an event

- Probability of event not happened = 1 - P(A)

- P(A and B) = P(A) . P(B)

* Lets solve the problem

- There is a group of students

- There are 8 boys and 12 girls in the group

∴ There are 8 + 12 = 20 students in the group

- The students are sent to represent the school in a parade

- Two students are chosen at random

∴ P(S) = 20

- The students that chosen are not both girls

∴ The probability of not girls = 1 - P(girls)

∵ The were 20 students in the group

∵ The number of girls in the group was 12

∴ The probability of chosen a first girl = 12/20

∵ One girl was chosen, then the number of girls for the second

choice is less by 1 and the total also less by 1

∴ The were 19 students in the group

∵ The number of girls in the group was 11

∴ The probability of chosen a second girl = 11/19

- The probability of both girls is P(1st girle) . P(2nd girl)

∴ The probability of both girls = (12/20) × (11/19) = 33/95

- To find the probability of both not girls is 1 - P(both girls)

∴ P(not both girls) = 1 - (33/95) = 62/95

* The probability that the students chosen are not both girls is 62/95

5 0

3 years ago

Please help! My teacher never taught us this.

PIT_PIT [208]

Answer:

200.96

Step-by-step explanation:

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3 years ago

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Based on a poll of 1000 residents, a newspaper article claims that 62% of the residents in town favor the development of a recre

nlexa [21]

Estimate of population 0.61
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3 years ago

Find the value of x and y

GarryVolchara [31]

Answer:

x = 60

y = 30

Step-by-step explanation:

We know that all triangles' interior angles combined must have a sum of 180.

Since the triangle on the left is a equilateral triangle, we know that each angle is equal to 60.

Since we already know that the sum of the two angles in the top right is 90 (shown by the right angle symbol) and we know that the angle that isn't y is equal to 60, we must do the following step:

90 - 60 = y

90 - 60 = 30

y = 30

Now that we know the value of y, it's time to find the value of x.

We know that y = 30 and that the angle in the bottom right is equal to 90 (shown by right angle symbol).

Since all triangles' interior angles combined must have a sum of 180 and we already know that one angle is equal to 30 and the other is equal to 90, we must do the following:

180 - (90 + y) = x

180 - (90 + 30) = x

180 - 120 = x

180 - 120 = 60

x = 60

This gives us the answers y = 30 and x = 60

7 0

3 years ago