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3 years ago

10

John worked "x" hours this week and Shanique worked eight hours less than John. Write an algebraic expression for the number of

hours that Shanique worked this week.

1 answer:

sergij07 [2.7K]3 years ago

6 0

Answer:

X>8

Step-by-step explanation:

X>8

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Find the volume of this

11111nata11111 [884]

Answer:

37.8 yd^3

Step-by-step explanation:

base area = (4.5 x 2.8)/2 = 6.3 yd^2

Volume = 6.3 x 6 = 37.8 yd^3

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2 years ago

Select the correct answer. what is the solution set of y = x2 2x 7 and y = x 7? a. {(0, 7), (-1, 6)} b. {(0, 7), (-7, 0)} c. {(0

Kaylis [27]

Answer:

a. {(0, 7), (-1, 6)}

Step-by-step explanation:

$y = x^{2} +2x+7\\y=x+7$

subtract the equations

$y = x^{2} +2x+7 \\- \ \ \ \ \ y=x+7\\y - y =x^{2} +2x+7-(x+7)\\0=x^{2} +x\\x = 0 \ and \ x= -1$

for $y = x^{2} +2x+7$ , substitute x = 0

$y = (0)^{2} +2(0)+7\\y = 0 +0+7\\y=7$

for $y = x^{2} +2x+7$ , substitute x = 0

$y = (-1)^{2} +2(-1)+7\\y = 1 -2+7\\y=6$

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1 year ago

Mary is solving the equation 2n – 3 = 83. Her first three steps are shown:

Stells [14]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
2^n - 3 = 83
<span>2^n = 86 </span>
<span>ln(2^n) = ln(86) </span>
<span>n*ln(2) = ln(86) </span>
<span>n= ln(86)/[ln(2)] (which is the same as "log base 2 of 86") </span>
<span>n= 6.426264755</span>

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3 years ago

The function f(x)=4(2)^x represent the number of people who share a cat video x hours after it first appears on a website. How d

Harlamova29_29 [7]

Answer:The number doubles each Hour Apex :)

Step-by-step explanation:

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3 years ago

Read 2 more answers

Which of these limits evaluate to 0?

Vikentia [17]

<h3>Answer: C) I and II only</h3>

===============================================

Work Shown:

Part I

$\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\$

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Part II

$\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\$

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Part III

$\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\$

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2 years ago