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lara31 [8.8K]
3 years ago
12

Jeffrey plans to rent a beach house for sister's birthday and will use the savings to pay for it the company charges to $25 clea

ning fee plus $10 per hour for the house if he rents the house for six hours what will the change in Jeffrey savings
Mathematics
1 answer:
balu736 [363]3 years ago
5 0
He will be using $85 for all of that
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Brianna bought a compact disk for $10. An instant rebate gave her a discount and she only had to pay $7.50 for the CD. What is t
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3 years ago
Question 2 2.1 2.2 2.2.1 2.2.2 Determine the general solution for sin(x - 30°) = cos 2x Consider the functions f(x) = sin(x-30°)
OLEGan [10]

The general solution for the given equation is 40°+120°n.

The period of g(x) is π.

The range of f(x) is [-1, 1].

  • sin(x-30°) = cos 2x
  • sin(x-30°) = sin(90°-2x)
  • (x-30°) = (90°-2x) + 360°n
  • x + 2x =  90° + 30° + 360°n
  • 3x = 120° + 360°n
  • x = (120° + 360°n)/3
  • The general solution (x) is 40° + 120°n.
  • g(x) = cos 2x
  • The period of cos x is 2π.
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  • Here, in g(x), n is 2.
  • The period of g(x) is equal to half the period of cos x.
  • The period of g(x) = 2π/2
  • The period of g(x) is π.
  • f(x) = sin(x-30°)
  • "Sin" is a trigonometric function which has a range from -1 to 1.

To learn more about  period, visit :

brainly.com/question/12539110

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5 0
1 year ago
Use​ l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove
steposvetlana [31]

Answer:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}

Step-by-step explanation:

The limit is:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}

by replacing, and applying repeatedly you obtain:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}

hence, the limit of the function is -1/14

8 0
3 years ago
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