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Mashcka [7]
2 years ago
9

A flower shop charged $124.44 for 3 bouquets of flowers. This price included a $7.50 service and delivery fee.

Mathematics
1 answer:
Colt1911 [192]2 years ago
5 0
The cost of one bouquet is - $41.48 but then u have to divide the shipping and delivery fee - $2.5 so then u add $41.48 + $2.5 = $43.98
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Read the following and answer the questions that follow.
user100 [1]

Answer:

Step-by-step explanation:

(7/12) of 840 attended the concert:

(7/12)*(840) = 490 students attended the Spring Concert.

(840 - 490) = 350 did not attend

(350/840) is the fraction of students who did not attend.  This can be reduced to (35/84)

(350/840) = 0.4167 or 41.67% did not attend.  

3 0
2 years ago
Standard normal curve between z=.42 and z=1.92<br> a= .6902<br> b= .3098<br> c= .1902<br> d= .8098
soldier1979 [14.2K]
The correct answer is Choice B: 0.3098.

To find the answer, you have to use a normal distribution table. Look up the percents for each z-score and subtract them to find the region between.

z = 1.92 the percent is 0.9726

z = 0.42 the percent is 0.6628

0.9726 - 0.6628 = 0.3098
4 0
3 years ago
At his new job, Jeremiah can choose an hourly rate of $9 plus a $50 weekly bonus for opening the store, or an hourly rate of $10
likoan [24]
The equations would be:
y=9x +50
y=10x

3 0
2 years ago
5.2 x 10^-3 ____ 5.2 x 10^-6
soldi70 [24.7K]
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hope this answers ur question!!
6 0
3 years ago
A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa
Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = \frac{12!}{3! 3! 3! 3!}

Now,

The Total number of ways in which Remaining cards are distributed = \frac{40!}{10! 10! 10! 10!}

So,

Total number of ways of getting 3 picture card and remaining card = \frac{12!}{3! 3! 3! 3!}× \frac{40!}{10! 10! 10! 10!}

= \frac{12! 40!}{(3!)^{4} (10!)^{4}  }

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = \frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }

∴ The probability = \frac{\frac{12! 40!}{(3!)^{4} (10!)^{4}  }}{\frac{52!}{(13!)^{4} }}

                            = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13!)^{4} }{ 52! }

                           = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }

                           = \frac{12!}{(3!)^{4}   }×\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = \frac{479,001,600}{(6)^{4}   }×\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

6 0
2 years ago
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