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garri49 [273]
4 years ago
11

Find −1/5+17/10. Please help me!

Mathematics
1 answer:
alina1380 [7]4 years ago
7 0
I got 1.5, but I could be wrong.
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A professor claims that his students' average score on the first exam of the semester is different than the average score on the
Marta_Voda [28]

Answer:

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=0.704

p_v = 2*P(t_{7} >0.704)=0.504

So the p value is higher the significance level given 0.1, so then we can conclude that we FAIL to reject the null hypothesis that the difference mean between after and before score is equal 0. So then we don't have enough evidence to say that the score for the second exam is different than the score for the first exam.

Step-by-step explanation:

Previous concepts

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations (This problem) we can use it.  

Let put some notation  

x=test value before (first exam) , y = test value after (second exam)

The system of hypothesis for this case are:

Null hypothesis: \mu_y -\mu_x =0

Alternative hypothesis: \mu_y -\mu_x \neq 0

The first step is calculate the difference d_i=y_i-x_i

The statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=0.704

The next step is calculate the degrees of freedom given by:

df=n-1=8-1=7

Now we can calculate the p value, since we have a left tailed test the p value is given by:

p_v = 2*P(t_{7} >0.704)=0.504

So the p value is higher the significance level given 0.1, so then we can conclude that we FAIL to reject the null hypothesis that the difference mean between after and before score is equal 0. So then we don't have enough evidence to say that the score for the second exam is different than the score for the first exam.

5 0
3 years ago
What is the completely factored form of this polynomial?<br> 5x^4 + 20x^3 - 105x^2
pickupchik [31]

Answer:

5x^{2}(x - 3)(x + 7)

Step-by-step explanation:

Hope this helps! have a nice day! Please consider making me Brainliest!

5 0
3 years ago
How to solve the question
Scorpion4ik [409]
You have the equations set up correctly. I will use r and b as the variables to make it easier to follow.

12r + 8b = 70
20r + 12b = 110

First let's solve one of the equations for one of the variables.

12r = 70 - 8b

r =  \frac{70-8b}{12}

Now plug that in for r in the second equation.

20( \frac{70-8b}{12})+12b = 110

Simplify

20(70-8b)+144b=1320

1400-160b+144b=1320

-16b = -80

b = 5 grams

Now plug 5 in for b in one of the original equations to find r.

12r + 8(5) = 70

12r  = 30

r = 2.5 grams

So the red marbles weigh 2.5 grams, and the blue marbles weigh 5 grams.
3 0
4 years ago
What is the area of this figure?
Alborosie

Answer:

146

Step-by-step explanation:

Hey there to find the area of this shape we will divide it into 2 shapes first one is a trapezoid and the second one is a triangle. first, we find the area of a trapezoid. to find the area of a trapezoid we use the formula:

        A = \frac{a+b}{2} * h          

in this situation

a = 4

b = 14

h = 10

Now we plug it into the formula which will look like:

       A = \frac{4+14}{2}*10

if we solve it:

4+14 = 18

18/2 = 9

9*10 = 90

so the area of the trapezoid is 90

Now we find the area of triangle. to find the area of a triangle we use the formula:

   A = \frac{1}{2} * b * h

in this situation

b = 14

h = 8 ( because the height of the trapezoid was 10 and the height of both shapes combined is 18 so we do 18 - 10 = 8 )

Now we put the numbers into the formula  which will look like:

    A = \frac{1}{2}*14*8

if we solve it :

14*8 = 112

112*\frac{1}{2} = 56

so the area of the triangle is 56

Now we add the area of both shapes:

56 + 90 = 146

area of the big shape = 146

Have a wonderful day

7 0
3 years ago
Read 2 more answers
Hello I need a little help I need to hurry and finish this I am multi-tasking at the moment, I know this is easy but please answ
Fed [463]

Answer:

4×3×5

60

Answer

3 0
4 years ago
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